TypeError：draw_row（）在第55行正好采用5个参数（给定6个参数）

Question

我周五有家庭作业，但是我有一个问题，我的老师没有回复我，所以你能帮我吗？

我刚刚在学校开始使用python turtle，这是我编写的代码

from turtle import*

def square(square_color, length):
  pd()
  color(square_color)
  begin_fill
  for i in range(4):
    fd(length)
    lt(90)
  end_fill()
  pu()
  fd(length)

speed(0)
n= int(input("Enter a number:"))
pu()
bk(n*25)
pu()
bk(n*25)

for cur_square in range(n):
  if cur_square % 2 ==0:
    square("black", 50)
  if cur_square % 2 ==1:
    square("red", 50)
  if cur_square % 2 ==2:
    square("gray", 50)

def draw_row(rows, length, square1_color, square2_color, cur_square):
  for i in range(rows):
    if(cur_square + i)% 2 ==0:
      square(square1_color, length)
    if (cur_square + i )%2 ==1:
      square(square2_color, length)


def move_up(rows, length):
  lt(90)
  fd(length)
  rt(90)
  bk(rows*length)


length = int(input("The length of one square: "))
rows = int(input("The total amount of rows:"))
color1 = input("Color of the first square:")
color2 = input("Color of the second square:")
color3 = input("Color of the third square:")

speed(0)
pu()
setpos(-rows/2 * length, -rows/2 * length)

for cur_square in range(rows):
  draw_row(rows, length, color1, color2, color3, cur_square)
  move_up(rows,length)

它告诉我我有一个错误-TypeError：draw_row（）恰好在第55行采用了5个参数（给定6个）

我该怎么办？

确切的行我有错误

for cur_square in range(rows):
      draw_row(rows, length, color1, color2, color3, cur_square)
      move_up(rows,length)

Answer 1

错误消息很清楚，您定义draw_row()接受五个参数：

def draw_row(rows, length, square1_color, square2_color, cur_square):

然后是时候调用它了，您通过了六个：

draw_row(rows, length, color1, color2, color3, cur_square)

按照定义，draw_row()仅处理square1_color和square2_color这两种颜色：

def draw_row(rows, length, square1_color, square2_color, cur_square):
    for i in range(rows):
        if (cur_square + i) % 2 == 0:
            square(square1_color, length)
        else:
            square(square2_color, length)

但是当您调用它时，您传递了color1，color2和color3这三种不同的颜色。