如何将c中的整数位字段连接为uint64_t整数？

Question

我在c中有这样的结构

struct RegisterStruct
{
    uint64_t b_0 : 64;
    uint64_t b_1 : 64;
    uint64_t c_0 : 64;
    uint64_t c_1 : 64;
    uint64_t c_2 : 64;
    uint64_t d_0 : 64;
    uint64_t d_1 : 64;
};

我想将字段连接成一个uint64_t整数。每个字段应占据给定数量的位，定义如下：

b_0: 4bits 
b_1: 4bits
c_0: 8bits
c_1: 8bits
c_2: 8bits
d_1: 16bits
d_2: 16bits

结果应该是一个uint64_t整数，其中包含连接的位域（从b_0到d_2），每个位域占据给定的位数。

这是我尝试过的，但我认为此解决方案不正确：

struct RegisterStruct Register;

   Register.b_0 = 8;
   Register.b_1 = 8;
   Register.c_0 = 128;
   Register.c_1 = 128;
   Register.c_2 = 128;
   Register.d_0 = 32768;
   Register.d_1 = 32768;

   uint64_t reg_frame =Register.b_0<<60|Register.b_1<<56|Register.c_0<<48|Register.c_1<<40|Register.c_2<<32|Register.d_0<<16|Register.d_1;

Answer 1

typedef union
{ 
    struct
    {
        uint64_t b_0 : 4;
        uint64_t b_1 : 4;
        uint64_t c_0 : 8;
        uint64_t c_1 : 8;
        uint64_t c_2 : 8;
        uint64_t d_0 : 16;
        uint64_t d_1 : 16;
    };
    uint64_t u64;
}R_t;


int main()
{

    R_t Register;

    Register.b_0 = 8;
    Register.b_1 = 8;
    Register.c_0 = 128;
    Register.c_1 = 128;
    Register.c_2 = 128;
    Register.d_0 = 32768;
    Register.d_1 = 32768;

    printf("%llx\n", (long long unsigned)Register.u64);
}

https://godbolt.org/z/_dYuz2