没有闰日的两个日期之间的差异

Question

我有开始日期和结束日期，我必须在这两个日期之间得到区别，但条件是，如果是闰年，我必须排除2月29日。我可以使用momentJS在两个日期之间获得差异。但如果它在那个日期范围内，如何排除第29个feb。

对于Ex：

//For Leap Year
var startDate = moment('2020-02-27')
var endDate = moment('2020-03-01')
console.log('Diff in leap year', endDate.diff(startDate, 'days')); //Result: 3



var startDate1 = moment('2018-02-27')
var endDate1 = moment('2018-03-01')
console.log('Diff in non leap year', endDate1.diff(startDate1, 'days')); //Result: 2 

<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.21.0/moment.min.js"></script>

我期待跳跃和非闰年的统一结果，或者只是想从计算中排除第29个feb。差异可能超过一年。

有没有最佳解决方案呢？

Answer 1

使用.isLeapYear()，您可以在日期范围之间迭代所有年份并获得预期结果

function dateDiff(startStr, endStr) {
  var startDate = moment(startStr);
  var endDate = moment(endStr);
  var diff = endDate.diff(startDate, 'days');
  for (var year = startDate.year(); year <= endDate.year(); year++) {
    var date = moment(year + '-02-29');
    if (date.isBetween(startDate,endDate) && date.isLeapYear()) {
        diff -= 1;
    }
  }
  return diff;
}

console.log(dateDiff('2020-02-27', '2020-03-01'));
console.log(dateDiff('2018-02-27', '2018-03-01'));

Answer 2

您可以使用.isLeapYear()检查它是否是闰年，如果是，则从结果中减去一天：

function diffDates(startDate, endDate) {
  var diff = endDate.diff(startDate, 'days');

  while(startDate < endDate) {
    if(startDate.isLeapYear() && 
      moment(`${startDate.year()}-02-29`).isBetween(startDate, endDate)) {
      diff--;
    }
    startDate.year(startDate.year() + 1);
  }
  return diff;
}

var startDate = moment('2020-02-27')
var endDate = moment('2020-03-01')

console.log('Leap year days diff: ' + diffDates(startDate, endDate)); // 2

startDate = moment('2018-02-27')
endDate = moment('2018-03-01')
console.log('Non leap year days diff: ' + diffDates(startDate, endDate)); // 2

startDate = moment('2019-02-27')
endDate = moment('2020-03-01')
console.log('Between leap year days diff: ' + diffDates(startDate, endDate)); // 367

我添加了一个条款，知道你的日期是否在使用.isBetween()的闰年之间的29日之间，并且每当闰日在间隔内时创建一个while循环从diff中减去1。

看到它工作here。

Answer 3

您可以使用startDate检查.isLeapYear()是否是闰年，然后相应地减去1。

function getDiff(startDate, endDate){
  var isLeapYear = startDate.isLeapYear();
  return endDate.diff(startDate, 'days') - (isLeapYear?1:0);
}


var startDate = moment('2020-02-27')
var endDate = moment('2020-03-01')
console.log('Diff in leap year', getDiff(startDate, endDate)); 

var startDate1 = moment('2018-02-27')
var endDate1 = moment('2018-03-01')
console.log('Diff in non leap year',getDiff(startDate1, endDate1));

<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.21.0/moment.min.js"></script>

Answer 4

你可以尝试这样的事情：

• 检查所选年份是否为闰年。
• 如果是，请检查日期范围是否涵盖29th Feb
• 如果是，则减去1，否则为0

function getDiff(startDate, endDate){
  var dayToExclude = moment('29/02/' + startDate.year(), 'DD/MM/YYYY');
  var excludeDays = startDate.isLeapYear() && startDate.isBefore(dayToExclude) && endDate.isAfter(dayToExclude) ? 1 : 0;
  return endDate.diff(startDate, 'days') - excludeDays;
}


var startDate = moment('2020-02-27')
var endDate = moment('2020-03-01')
console.log('Diff in leap year', getDiff(startDate, endDate)); 

var startDate1 = moment('2018-02-27')
var endDate1 = moment('2018-03-01')
console.log('Diff in non leap year',getDiff(startDate1, endDate1));

<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.21.0/moment.min.js"></script>