Hitomis圈菜单如何打开新活动

问题描述 投票:0回答:2

我正在使用Hitomis circle menu library但不知道如何在点击特定子菜单时打开特定活动?

我想在Hitomis库中没有这样的功能,但是如果有任何办法可以告诉我。

这是java代码

public class MainActivity extends AppCompatActivity {
private CircleMenu circleMenu;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    circleMenu = (CircleMenu) findViewById(R.id.circle_menu);
    circleMenu.setMainMenu(Color.parseColor("#CDCDCD"), R.mipmap.menuop, R.mipmap.menucl)
            .addSubMenu(Color.parseColor("#258CFF"), R.drawable.chrome)
            .addSubMenu(Color.parseColor("#30A400"), R.drawable.drive)
            .addSubMenu(Color.parseColor("#FF4B32"), R.drawable.googlesearch)
            .addSubMenu(Color.parseColor("#8A39FF"), R.drawablegmail)
            .addSubMenu(Color.parseColor("#FF6A00"), R.drawable.youtube)
            .setOnMenuSelectedListener(new OnMenuSelectedListener() {
                @Override
                public void onMenuSelected(int index) {}

            }).setOnMenuStatusChangeListener(new OnMenuStatusChangeListener() {

                @Override
                public void onMenuOpened() { }

                @Override
                public void onMenuClosed() {}

            });
}
android android-activity
2个回答
0
投票

菜单选择的监听器返回菜单的索引,如果单击第一个子菜单项addSubMenu(Color.parseColor("#258CFF"), R.drawable.chrome)它返回索引= 0,则单击该菜单的索引,现在如果要在特定子菜单上打开活动,则可以执行以下操作

setOnMenuSelectedListener(new OnMenuSelectedListener() {
                    @Override
                    public void onMenuSelected(int index) {
       switch(index){
    case 0: startActivity(new Intent(this,FirstActivity.class));break;
    case 1: startActivity(new Intent(this,SecondActivity.class));break;
       }
    }

0
投票

你也可以使用if

.setOnMenuSelectedListener(new OnMenuSelectedListener() {
    @Override
    public void onMenuSelected(int i) {
        if (i==0){
        Intent intent = new Intent(MainActivity.this,FirstActivity.class);
        startActivity(intent);
        }
        if (i==1){
            Intent intent = new Intent(MainActivity.this,SecondActivity.class);
            startActivity(intent);
        }
    }
});
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