我在查询解析服务器时遇到问题。我创建了一个名为Tickets的类,并通过仪表板创建了一行。使用curl时,我可以查询并获取行。但是,当我尝试从HTML页面使用JavaScript进行操作时,结果为零。
我从myLogin调用getTickets()函数,这是通过单击按钮来调用的。在getTickets()中进行的最终console.log()调用将显示“结果:”,而不会显示其他任何内容。
顺便说一句,getTickets()函数以Parse文档中的examples为模型。
感谢您的帮助。
这是我的代码:
Parse.initialize("-REDACTED-", "");
Parse.serverURL = "-REDACTED-";
function myLogin(uname, psw) {
var uname = document.getElementById("uname").value;
var psw = document.getElementById("psw").value;
const user = Parse.User.logIn(uname, psw);
var cUser = Parse.User.current();
if (cUser) {
console.log(
"Hey! The login worked!" + " Username: " + cUser.get("username")
);
getTickets();
} else {
alert("Womp, womp. The login failed.");
}
}
async function getTickets() {
const Ticket = Parse.Object.extend("Ticket");
const query = new Parse.Query(Ticket);
const res = await query.find();
console.log("Results: " + res);
}
curl调用返回以下内容,如果有用的话:
{"results":[{"objectId":"RuFPxSjigL","user":{"__type":"Pointer","className":"_User","objectId":"uGwwN99EX9"},"createdAt":"2020-01-15T20:47:45.116Z","updatedAt":"2020-01-15T20:48:05.203Z","event":{"__type":"Pointer","className":"Event","objectId":"BdGQSPhK0J"}}]}%
我找到了答案。我不明白Parse.Query.find()返回一个数组。 getTickets()中的console.log()调用指示res未定义,我认为什么也没有返回。我更新了代码以使其表现更好。我是JavaScript新手,对于改进代码或样式的任何建议,我将不胜感激。
Parse.initialize("imAppId", "");
Parse.serverURL = "https://www.immedia.co/parse/";
async function imLogin(uname, psw) {
var uname = document.getElementById("uname").value;
var psw = document.getElementById("psw").value;
var user;
try {
user = await Parse.User.logIn(uname, psw);
} catch (err) {
alert("Login failed: username or password are not valid: ", err);
}
const tix = await getTickets();
for (let i = 0; i < tix.length; i++) {
var obj = tix[i];
console.log(
"ticket.id: " + obj.id + " with user.id " + obj.get("user")
);
}
async function getTickets() {
const Ticket = Parse.Object.extend("Ticket");
const query = new Parse.Query(Ticket);
var tix = [];
try {
tix = await query.find();
alert("Successfully retrieved " + tix.length + " tickets.");
} catch (err) {
console.error("Error getting tickets: ", err);
}
return tix;
}
我有一些小事情要改变: