SQL模型中的日期列到ASP.NET模型中的System.DateTime

问题描述 投票:2回答:1

我在date_creation_user类型的SQL Server数据库中有一个date列。我使用Entity Framework(数据库优先)所以在User模型类中我有:

public System.DateTime date_creation_user { get; set; }

我用POST和GET方法创建了我的Web API。

对于POST我输入数据:

{
    //
    "Date_creation_user": "2019-04-12"
}

使用Get,结果是:

{
    "Client_ID": 1,
    "Date_creation_user": "2012-02-24T00:00:00",
}

我想获得一个明确的DATE格式,因为我需要一个GET方法,让所有用户都有创建日期,我该如何实现该方法?

这是我的两个GET方法和我的POST:

得到所有 :

[HttpGet]
//[Authorize]
public async Task<HttpResponseMessage> Get()
{
    List<ClientModel> model = new List<ClientModel>();

    try
    {
        clService.GetClients().ToList().ForEach(a =>
        {
            ClientModel compts = new ClientModel
            {
                Client_ID = a.Client_ID,
                Type_Client = a.Type_Client,
                Date_creation_user = a.Date_creation_client

            };

            model.Add(compts);

        });
        return Request.CreateResponse(HttpStatusCode.OK, model);
    }
    catch (Exception ex)
    {
        return Request.CreateResponse(HttpStatusCode.BadRequest, ex);
    }
}

GET ID:

[HttpGet]
public HttpResponseMessage find(int id)
{
    try
    {
        var result = new HttpResponseMessage(HttpStatusCode.OK);
        result.Content = new StringContent(JsonConvert.SerializeObject(clService.GetClient(id)));
        result.Content.Headers.ContentType = new MediaTypeHeaderValue("application/json");
        return result;
    } 
    catch
    {
        return new HttpResponseMessage(HttpStatusCode.BadRequest);
    }
}

POST:

[HttpPost]
public HttpResponseMessage CreateClient(CLIENT Client)
{
    try
    {
        var result = clService.AjoutClient(Client);
        return Request.CreateResponse(HttpStatusCode.Created, result);
    }
    catch (Exception ex)
    {
        return Request.CreateResponse(HttpStatusCode.InternalServerError, ex.Message);
    }
}

如何使用date参数实现该GET方法?

谢谢

c# sql asp.net sql-server date
1个回答
0
投票

改变这一行:

Date_creation_user = a.Date_creation_client.ToString("yyyy-MM-dd")
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