如何隐藏空子类别(WordPress)

问题描述 投票:0回答:3

我使用下面的代码显示空子类别,其中没有任何帖子,我想隐藏这些。如果有可能,请允许我,如果是,那么如何

<?php
    $term = get_queried_object();
    $term_id = $term->term_id;
    $taxonomy_name = $term->taxonomy;

    $termchildren = get_term_children( $term_id, $taxonomy_name );

    echo '<ul>';
    foreach ( $termchildren as $child ) {
        $term = get_term_by( 'id', $child, $taxonomy_name );
        echo '<li><a href="' . get_term_link( $term, $taxonomy_name ) . '">' . $term->name.' ('. $term->count. ')</a></li>';
    }
    echo '</ul>';
?>

非常感谢提前

wordpress
3个回答
0
投票

您可以使用$term->count检查它是否有任何帖子。

foreach ( $termchildren as $child ) {
    $term = get_term_by( 'id', $child, $taxonomy_name );
    if($term->count > 0){
       echo '<li><a href="' . get_term_link( $term, $taxonomy_name ) . '">' . $term->name.' ('. $term->count. ')</a></li>';
    }
}

0
投票

我有另一个解决方案

$termchildren = get_terms( $taxonomy_name, array( 'hide_empty' => true, 'parent' => $term_id ) );

0
投票

您可以使用术语计数来检查空类别

 $term = get_queried_object();
$term_id = $term->term_id;
$taxonomy_name = $term->taxonomy;

$termchildren = get_term_children( $term_id, $taxonomy_name );

echo '<ul>';
foreach( $termchildren  as $child  ) {
    $term = get_term_by( 'id', $child, $taxonomy_name );
    if( $term->count > 0 ) {
        echo '<li><a href="' . get_term_link( $term, $taxonomy_name ) . '">' . $term->name.' ('. $term->count. ')</a></li>';
    }
}
echo '</ul>';
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