复制文件时嵌套尝试捕获

Question

我正在从.csv中的文件位置复制文件，该文件不包含文件扩展名。我尝试对有效的'.tif'进行硬编码，但是还有其他文件类型被遗漏了。我尝试使用以下内容，但会引发错误，指出路径显示为C：\ users ...

    if (-not (Test-Path -Path $path -PathType Container)) {
        New-Item -Path $path -ItemType Directory >$null
    }
    #Perform Copy
    echo "Copying document and Prepending Document Date"

    try {
        $copy = [IO.FileInfo]$_.'Document File Path'+'.tif'
        $copy | Copy-Item -Destination "$path\$($_.'Document Date')_$($copy.Name)"
    } catch {
        try {
              $copy = [IO.FileInfo]$_.'Document File Path'+'.pdf'
              $copy | Copy-Item -Destination "$path\$($_.'Document Date')_$($copy.Name)"
        } catch {
            $copy = [IO.FileInfo]$_.'Document File Path'+'.jpg'
            $copy | Copy-Item -Destination "$path\$($_.'Document Date')_$($copy.Name)"
        } finally {
            $copy = [IO.FileInfo]$_.'Document File Path'+'.doc'
            $copy | Copy-Item -Destination "$path\$($_.'Document Date')_$($copy.Name)"
        }
    } finally {
        $copy = [IO.FileInfo]$_.'Document File Path'+'.docx'
        $copy | Copy-Item -Destination "$path\$($_.'Document Date')_$($copy.Name)"
    }
}

Answer 1

如果您一次只有一个匹配文件，则类似的事情应该起作用：

$name = Split-Path -Leaf $_.'Document File Path'
$src  = $_.'Document File Path'
$dst  = Join-Path $path ('{0}_{1}' -f $_.'Document Date', $name)
Get-ChildItem "${src}.*" | Copy-Item -Destination { $dst + $_.Extension }

[如果这会偶然地与您不想复制的其他文件匹配（例如$name为“ foo”，并且您想复制“ foo.tif”而不是“ foo.bar.txt”），则可以按复制前的基本名称：

Get-ChildItem "${src}.*" | Where-Object {
    $_.BaseName -eq $name
} | Copy-Item -Destination { $dst + $_.Extension }