如何获取数组所有可能的索引作为数字联合类型？

Question

如何获取数组所有可能的索引作为数字联合类型？

数字联合类型的预期结果：

type VoiceSettings = {
    similarityLevel: 0 | 1 | 2 | 3 | 4 | 5;
    stabilityLevel: 0 | 1 | 2 | 3 | 4;
}

实际结果：

type VoiceSettings = {
    similarityLevel: "0" | "1" | "2" | "3" | "4";
    stabilityLevel: "0" | "1" | "2" | "3" | "4";
}

代码：

const VALUES_MAP = {
  similarityLevel: [0, 15, 30, 50, 75, 90],
  stabilityLevel: [15, 30, 60, 75, 90],
} as const;

type ValuesTypes = keyof typeof VALUES_MAP;

type VoiceSettings = {
  [key in ValuesTypes]: Exclude<keyof (typeof VALUES_MAP)[ValuesTypes], keyof []>;
};

这里是TS游乐场

Answer 1

来自这个答案关于我提出的重复问题：

您可以使用以下类型：

type Indices<T extends readonly any[]> = Exclude<Partial<T>["length"], T["length"]>

对于你的问题，看起来像这样：

const VALUES_MAP = {
  similarityLevel: [0, 15, 30, 50, 75, 90],
  stabilityLevel: [15, 30, 60, 75, 90],
} as const;

type ValuesTypes = keyof typeof VALUES_MAP;

type Indices<T extends readonly any[]> = Exclude<Partial<T>["length"], T["length"]>

type VoiceSettings = {
  [key in ValuesTypes]: Indices<typeof VALUES_MAP[key]>;
};

其中

VoiceSettings

输入为：

type VoiceSettings = {
  similarityLevel: 0 | 5 | 1 | 2 | 3 | 4;
  stabilityLevel: 0 | 1 | 2 | 3 | 4;
}

这里是TS游乐场