在codeigniter上输入html,

问题描述 投票:1回答:2

我有使用bootstrap的HTML,它是这样编写的:

<div class="form-group">
  <label class="control-label col-md-3">PIB Ajuan</label>
    <div class="col-md-9">
          <input name="pibaju" id="pibaju" class="form-control" type="text">
          <span class="help-block"></span>
    </div>
</div>

我如何转换它,以便它使用CodeIgniter的表单助手https://www.codeigniter.com/user_guide/helpers/form_helper.html

php twitter-bootstrap codeigniter
2个回答
3
投票

很简单:

<?php
$input_pibaju = array(
 "type" => "text",
 "name" => "pibaju",
 "id" => "pibaju",
 "class" => "form-control"
);
echo form_input($input_pibaju);
?>

代替

<input name="pibaju" id="pibaju" class="form-control" type="text">

编辑:在您的Controller中,您必须在加载视图文件之前调用form_helper:

$this->load->helper('form');

1
投票

试试这个

首先,您需要加载表单助手

$this->load->helper('form');

然后你可以用它

<div class="form-group">
  <label class="control-label col-md-3">PIB Ajuan</label>
  <div class="col-md-9">
      <?= form_input(['name'=>'pibaju','id'=>'pibaju','class'=>'form-control']) ?>
      <span class="help-block"></span>
  </div>
</div>
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