我有蟒蛇的文件结构的任何地方为:
flaskhost(文件夹),其包含:
app.py包含 - :
import flask
from flask import request, jsonify
import sqlite3
app = flask.Flask(__name__)
app.config["DEBUG"] = True
def dict_factory(cursor, row):
d = {}
for idx, col in enumerate(cursor.description):
d[col[0]] = row[idx]
return d
@app.route('/', methods=['GET'])
def home():
return '''<h1>Distant Reading Archive</h1>
<p>A prototype API for distant reading of science fiction novels.</p>'''
@app.route('/api/v1/resources/books/all', methods=['GET'])
def api_all():
conn = sqlite3.connect('books.db')
conn.row_factory = dict_factory
cur = conn.cursor()
all_books = cur.execute('SELECT * FROM books;').fetchall()
return jsonify(all_books)
@app.errorhandler(404)
def page_not_found(e):
return "<h1>404</h1><p>The resource could not be found.</p>", 404
@app.route('/api/v1/resources/books', methods=['GET'])
def api_filter():
query_parameters = request.args
id = query_parameters.get('id')
published = query_parameters.get('published')
author = query_parameters.get('author')
query = "SELECT * FROM books WHERE"
to_filter = []
if id:
query += ' id=? AND'
to_filter.append(id)
if published:
query += ' published=? AND'
to_filter.append(published)
if author:
query += ' author=? AND'
to_filter.append(author)
if not (id or published or author):
return page_not_found(404)
query = query[:-4] + ';'
conn = sqlite3.connect('books.db')
conn.row_factory = dict_factory
cur = conn.cursor()
results = cur.execute(query, to_filter).fetchall()
return jsonify(results)
if __name__ == '__main__':
app.run()
我想按照这个教程
https://programminghistorian.org/en/lessons/creating-apis-with-python-and-flask
我的网站托管在:
但是,当我通过调用API
http://127.0.0.1:5000/api/v1/resources/books?author=Connie+Willis
它告诉我的错误:
sqlite3.OperationalError:没有这样的表:书籍
任何帮助如何解决这一问题,并在pythonanywhere.com主机应用程序吗?
P.S在我的本地机器它的工作完全没有问题
在Pythonanywnere,当指着含量比模板或静态文件等(存储在自己的正确的目录,由flask
访问),你必须提供完整的路径:
conn = sqlite3.connect('/home/your_username/flaskhost/books.db')