如何从字符串数组中获取图像的ID

问题描述 投票:0回答:2

我为我的GridView创建了一个自定义适配器,它将显示一本书的图像(查看图像)及其名称(查看文本); ,我在字符串文件中声明了书名的列表:[strings.xml]

<string-array name="bookLabels">

    <item>android security</item>
    <item>penetration_testing</item>
    <item>red_team</item>
    <item>Linux Firewalls</item>
    <item>the_art_of_exploitation</item>
    <item>web_application_hacker</item>
    <item>Linux Basicsfor Hackers</item>
    <item>Black Hat Python</item>

</string-array>

所以我想对图像做同样的事情,而不是在代码中声明它们:

 private Integer[] bookImages =
        {
                R.drawable.android_security,
                R.drawable.penetration_testing,
                R.drawable.red_team,
                R.drawable.lf,
                R.drawable.the_art_of_exploitation,
                R.drawable.web_application_hacker,
                R.drawable.lbh,
                R.drawable.bhp

        };

我在名为“bookImages”的字符串数组中声明了图像的名称,

  <string-array name="bookImages">
    <item>@drawable/android_security</item>
    <item>@drawable/penetration_testing</item>
    <item>@drawable/red_team</item>
    <item>@drawable/lf</item>
    <item>@drawable/the_art_of_exploitation</item>
    <item>@drawable/web_application_hacker </item>
    <item>@drawable/lbh </item>
    <item>@drawable/bhp </item>
 </string-array>

然后我将声明的所有图像的位置恢复到“bookimagesfromstring”数组:

Resources resi = context.getResources();
bookImagesFromString = resi.getStringArray(R.array.bookImages);
System.out.println("bookImages Images test 1: " + 
Arrays.toString(bookImagesFromString))

这是[主要活动]的源代码

public class main extends AppCompatActivity {
String[] labels;
String[ ] pages;
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main2);


    Resources res = getResources();
    labels = res.getStringArray(R.array.bookLabels);
    pages = res.getStringArray(R.array.web_pages);

    GridView gridView = findViewById(R.id.gridView1);
    BookGrid myAdapter = new BookGrid(getApplicationContext(), labels);
    gridView.setAdapter(myAdapter);


    gridView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
        public void onItemClick(AdapterView<?> parent, View v,
                                int position, long id) {

            Toast.makeText(
                    getApplicationContext(),
                    ((TextView) v.findViewById(R.id.gridtextView))
                            .getText(), Toast.LENGTH_SHORT).show();

           // Intent webPageIntent = new Intent(getApplicationContext(), 
          DisplayWebPage.class);
          //  webPageIntent.putExtra("WEB_PAGE", pages[ position ] );

           // startActivity( webPageIntent );



        }
    });
}

}

和[BookGrid类]

public class BookGrid extends BaseAdapter {
private Context context;
private LayoutInflater inflater;
private String[] imageName;
private String[] bookImagesFromString;

private Integer[] bookImages =
        {
                R.drawable.android_security,
                R.drawable.penetration_testing,
                R.drawable.red_team,
                R.drawable.lf,
                R.drawable.the_art_of_exploitation,
                R.drawable.web_application_hacker,
                R.drawable.lbh,
                R.drawable.bhp

        };


public BookGrid(Context context, String[] imageName) {
    this.context = context;
    this.imageName = imageName;
    this.inflater = LayoutInflater.from(context);
}

@Override
public int getCount() {
    return bookImages.length;
}

@Override
public Object getItem(int position) {
    return position;
}

@Override
public long getItemId(int position) {
    return position;
}

@Override
public View getView(int position, View convertView, ViewGroup parent) {

    /*
    Resources rest = context.getResources();
    String[] labels = rest.getStringArray(R.array.bookLabels);
    System.out.println("bookImagess Tex: " + Arrays.toString(labels));

    */
    Resources resi = context.getResources();
    bookImagesFromString = resi.getStringArray(R.array.bookImages);
    System.out.println("bookImages Images test 1: " + Arrays.toString(bookImagesFromString));


    if (convertView == null) {
        convertView = inflater.inflate(R.layout.layout_grid_image, parent, false);
        TextView txtv = convertView.findViewById(R.id.gridtextView);
        ImageView imgv = convertView.findViewById(R.id.gridImageView);

        //To Avoid ArrayIndexOutOfBoundsException
        //boolean inBounds = (position >= 0) && (position <= imageName.length);

            txtv.setText(imageName[position]);

      //imgv.setImageResource(bookImagesFromString[position]);
        imgv.setImageResource(bookImages[position]);

    } else {

    }

    return convertView;
}

“bookImagesFromString”数组的结果如下:

(Qazxswpoi)

那么问题是如何将“bookImagesFromString”数组转换为包含每个图像的ID的数组? - 在此代码部分中使用它之后:

[res/drawable-v24/android_security.png, res/drawable-v24/penetration_testing.png, res/drawable-v24/red_team.png, res/drawable/lf.jpg, res/drawable-v24/the_art_of_exploitation.png, res/drawable-v24/web_application_hacker.png, res/drawable/lbh.png, res/drawable-v24/bhp.png]

谢谢。

android gridview android-drawable
2个回答
0
投票

尝试像这样的字符串数组:

 imgv.setImageResource(bookImagesID[position]); 

和适配器这样:

<string-array name="bookImages">
    <item>android_security</item>
    <item>penetration_testing</item>
    <item>red_team</item>
    <item>lf</item>
    <item>the_art_of_exploitation</item>
    <item>web_application_hacker</item>
    <item>lbh</item>
    <item>bhp</item>
</string-array>

希望有所帮助!


0
投票

对于I_A_Mok所说的图像名称,我只是说:

public class BookGrid extends BaseAdapter {
private Context context;
private LayoutInflater inflater;
private String[] imageName;
private Integer[] bookImages;

public BookGrid(Context context, String[] imageName) {
    this.context = context;
    this.imageName = imageName;
    this.inflater = LayoutInflater.from(context);

    Resources resi = context.getResources();
    String[] bookImagesFromString = resi.getStringArray(R.array.bookImages);
    bookImages = new Integer[bookImagesFromString.length];
    for (int i = 0; i < bookImagesFromString.length; i++) {
        bookImages[i] = (resi.getIdentifier(bookImagesFromString[i], "drawable", context.getPackageName()));
    }
}

@Override
public int getCount() {
    return imageName.length;
}

@Override
public Object getItem(int position) {
    return position;
}

@Override
public long getItemId(int position) {
    return position;
}

@Override
public View getView(int position, View convertView, ViewGroup parent) {
/*
Resources rest = context.getResources();
String[] labels = rest.getStringArray(R.array.bookLabels);
System.out.println("bookImagess Tex: " + Arrays.toString(labels));
*/
    if (convertView == null) {
        convertView = inflater.inflate(R.layout.layout_grid_image, parent, false);
    }
    TextView txtv = convertView.findViewById(R.id.gridtextView);
    ImageView imgv = convertView.findViewById(R.id.gridImageView);

    txtv.setText(imageName[position]);
    imgv.setImageResource(bookImages[position]);

    return convertView;
}
}

所以我有两个解决方案:

Context的方法:

<string-array name="bookImages">
    <item>android_security</item>
    <item>penetration_testing</item>
    <item>red_team</item>
    <item>lf</item>
    <item>the_art_of_exploitation</item>
    <item>web_application_hacker </item>
    <item>lbh </item>
    <item>bhp </item>
</string-array>

或者没有Context(这种方法比第一个public static Integer[] getIds(Context context, String[] str) { Integer[] bookID = new Integer[str.length]; for (int i = 0; i < str.length; i++) { bookID[i] = context.getResources().getIdentifier(str[i], "drawable", context.getPackageName()); } return bookID; } 更快):

Retrieving Resources in Android

这是完整的代码

public static Integer[] getIds(String[] str) {

    Integer[] bookID = new Integer[str.length];

    try {
        for (int i = 0; i < str.length; i++) {
            Class res = R.drawable.class;
            Field field = res.getField(str[i]);
            int drawableId = field.getInt(null);
            bookID[i] = drawableId;
        }
    } catch (Exception e) {
        Log.e("MyTag", "Failure to get drawable id.", e);
        e.printStackTrace();

    }
    return bookID;
}

}

谢谢。

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