如何使按钮不成为OnClick窗口的一部分？

Question

[每当我单击按钮时，就会调用功能窗口onClick。我希望先调用按钮功能，然后再调用窗口。如何使函数依次调用？

window.onclick = myFunction;
function myFunction() {
  document.getElementById("demo").innerHTML = "∠CAD=∠DAE (AD bisects ∠CAE)";
  document.getElementById("demo2").innerHTML = "Select one of the statements to continue:";
  document.getElementById("button1").className = 'button1';
  document.getElementById("button2").className = 'button2';

window.onclick = myFunction2;
function myFunction2() {
    document.getElementById("demo4").innerHTML = "Now let’s complete the proof! Select the next statement:";
        document.getElementById("button3").className = 'button3';
  document.getElementById("button4").className = 'button4';
}

 window.onclick = myFunction3;
function myFunction3() {
    $("#button3").animate({
//    top: $("#demo3").parent().width() / 2,
top: "-250",
    left:"+600"
}, 2000);

}     
}

 $(document).ready(function(){
  $("#button1").click(function(){
      $("#button1").fadeOut();
    $("#button2").fadeOut();
    $("#demo2").fadeOut();
    $("#demo3").fadeIn();
  });

  $("#button3").click(function(){
      $("#tick").fadeIn();
      $("#button4").attr('disabled','disabled');


  });

  $("#button4").click(function(){
      $("#cross").fadeIn();
      $("#speech").fadeIn();
  });

});

Answer 1

[不介意使用window.onClick的错误方式，而只是关注主要问题，请使其他按钮不属于window.onClick。window.onClick获得所有单击页面的事件，所以为什么不对您的window.onClick加上条件。

window.onclick = myFunction;

function myFunction(event) {
  var btn = event.target.className;
  if (btn == "not-part") {
    console.log("this will not trigger the other part of the function");
  } else {
    // Your other codes here
  }
}

<button class="part">CLICK ME</button>
<button class="not-part">DON'T CLICK ME</button>