如何避免使用c ++中的libssh scp命令压缩从远程ssh下载的图像,音频和视频文件?

问题描述 投票:1回答:1

我正在尝试下载存储在远程计算机上的少量文件。这些文件可以是文本文件,图像文件(jpeg,jpg格式),视频或音频文件。文本文件下载成功没有问题,我也可以在我下载它们的本地机器上打开它。但是下载后图片文件和其他视频,音频文件无法打开。当我检查时,它们与原始文件的大小不同。就像说原始文件是30kb,但下载的文件只有5kb。这就是我下载后可能无法在本地打开这些文件的原因?我正在使用scplibssh功能。以下是我的尝试:

#include <iostream>
#include <string>
#include <libssh.h>
#include <stdlib.h>
#include <fstream> 
#include <stdio.h>
#include <Windows.h>
#include <fcntl.h>
#include <sstream>
#include <io.h>
using namespace std;

static int fetch_files(ssh_session session){
    int size;
    //char buffer[16384];
    int mode;
    int rc;
    //creating scp session to read from remote host for this file
    ssh_scp scp = ssh_scp_new(session, SSH_SCP_READ | SSH_SCP_RECURSIVE, "/home/snaps.jpg");


    //executing the init
    rc = ssh_scp_init(scp);

    //pulling from request object
    rc = ssh_scp_pull_request(scp);
    if (rc != SSH_SCP_REQUEST_NEWFILE)
    {
        std::cout << "Error receiving information about file: rc != SSH_SCP_REQUEST_NEWFILE";
        return -3;
    }
    else {
        //trying to download the file from the created scp object
        int t_filesize = ssh_scp_request_get_size(scp);
        cout << "filesize is = " << t_filesize;
        string t_filename = strdup(ssh_scp_request_get_filename(scp));
        cout << "File name read is = " << t_filename;
        int t_filemode = ssh_scp_request_get_permissions(scp);
        cout << "File mode is = " << t_filemode;
        //fprintf(stderr, "Receiving file %s, size %d, permisssions 0%o\n", t_filename, t_filesize, t_filemode);
        FILE *fptr = fopen("file.jpg", "w");
        if (NULL == fptr)
        {
            fprintf(stderr, "Error opening local file: %s, error %s\n", t_filename, strerror(errno));
            ssh_scp_deny_request(scp, "Unable to open local file");

        }
        ssh_scp_accept_request(scp);

        while (rc >= 0)
        {   //reading and storing into buffer to write on local file system
            rc = ssh_scp_read(scp, buffer, sizeof(buffer));
            cout << "Buffer = " << buffer;
            //cout << "RC = " << rc << " and SSH_ERROR is = " << SSH_ERROR;
            if (rc == SSH_ERROR)
            {
                fprintf(stderr, "Error receiving file data: %s\n", ssh_get_error(session));
                fclose(fptr);
                ssh_scp_close(scp);
                ssh_scp_free(scp);
                return rc;
            }
            //fprintf(stderr, "Bytes received = %d\n", rc);
            if (fwrite(buffer, rc, 1, fptr) != t_filesize)
            {
                fprintf(stderr, "Error writing file data: %s\n", strerror(errno));
                fclose(fptr);
                ssh_scp_close(scp);
                ssh_scp_free(scp);
                return rc;
            }
        } 
        cout << "Buffer is = " << buffer;
        fclose(fptr);

    }

请让我知道如何解决它。另外,如果您需要任何其他详细信息,请告知我们。

c++ ssh scp libssh
1个回答
3
投票
if (fwrite(buffer, rc, 1, fptr) != t_filesize)

本来应该

if (fwrite(buffer, 1, rc, fptr) != rc)

要么

if (fwrite(buffer, rc, 1, fptr) != 1)

rc1被交换。你打算写rc字节,第二个参数是每个单位的大小,第三个是单位数。既没有与t_filesize有任何关系。


while (rc >= 0)

不足,您还需要一个计数器来接收已接收的总字节数。在rc的循环增量中,如果total >= t_filesize中断。


rc = ssh_scp_read(scp, buffer, sizeof(buffer));

延展到

rc = ssh_scp_read(scp, buffer, min(sizeof(buffer), t_filesize - total));

因此,您不要求读取不可用的字节。


至于为什么你的文件太小,这是因为你遇到了首先提到的错误的错误处理。您只获得第一个缓冲区已满(因为缓冲区未完全使用,分别不是这样),并且您已经从传输中返回。

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