将每个具有相同名称的对象放入单个字典python

Question

我有以下词典列表：

[{'id': '1'},
 {'name': 'test'},
 {'email': '[email protected]'},
 {'id': '2'},
 {'name': 'supra'},
 {'email': '[email protected]'},
 {'id': '3'},
 {'name': 'gtr'},
 {'email': '[email protected]'}]

我想要的是：

data_list = [{"id":"1", "name":"test", "email":"[email protected]"},
             {"id":"2", "name":"supra", "email":"[email protected]"},
             ...]

我尝试过的：

v = [{k: v for d in data_list for k, v in d.items()}]

但是上面的代码只更新了相同键名的最后一个对象原因。

知道如何解决这个问题吗？谢谢。

Answer 1

假设

d

是一致的，您可以使用以下（hacky）解决方案按 3 组进行迭代：

ids = names = emails = iter(d)
data_list = [
    {
        'id': i['id'],
        'name': n['name'],
        'email': e['email']
    } for i, n, e in zip(ids, names, emails)
]

结果：

[{'id': '1', 'name': 'test', 'email': '[email protected]'}, {'id': '2', 'name': 'supra', 'email': '[email protected]'}, {'id': '3', 'name': 'gtr', 'email': '[email protected]'}]

更简单（由@fsimonjetz 建议）和我最喜欢的一个：

ids = names = emails = iter(d)
data_list = [i | n | e for i, n, e in zip(ids, names, emails)]

Answer 2

使用带有

range

切片的简单列表+字典理解：

N = 3
out = [{k:v for d in data_list[i:i+N] for k,v in d.items()}
       for i in range(0, len(data_list), N)]

这使得它很容易推广到任何

N

.

变体（不是更快）：

from collections import ChainMap

N = 3
out = [dict(ChainMap(*data_list[i:i+N])) for i in range(0, len(data_list), N)]

输出：

[{'id': '1', 'name': 'test', 'email': '[email protected]'},
 {'id': '2', 'name': 'supra', 'email': '[email protected]'},
 {'id': '3', 'name': 'gtr', 'email': '[email protected]'}]

使用的输入：

data_list = [{'id': '1'},
             {'name': 'test'},
             {'email': '[email protected]'},
             {'id': '2'},
             {'name': 'supra'},
             {'email': '[email protected]'},
             {'id': '3'},
             {'name': 'gtr'},
             {'email': '[email protected]'}]

Answer 3

如果保证你的输入列表是三人一组，那么：

_list = [
    {
        "id": "1"
    },
    {
        "name": "test"
    },
    {
        "email": "[email protected]"
    },
    {
        "id": "2"
    },
    {
        "name": "supra"
    },
    {
        "email": "[email protected]"
    },
    {
        "id": "3"
    },
    {
        "name": "gtr"
    },
    {
        "email": "[email protected]"
    }
]

data_list = []

for i in range(0, len(_list), 3):
    data_list.append(_list[i] | _list[i+1] | _list[i+2])

print(data_list)

输出：

[{'id': '1', 'name': 'test', 'email': '[email protected]'}, {'id': '2', 'name': 'supra', 'email': '[email protected]'}, {'id': '3', 'name': 'gtr', 'email': '[email protected]'}]