ProcessStartInfo.Arguments接受带有双引号的多个参数

Question

string CandlePath = "C:\\Program Files (x86)\\WiX Toolset v3.11\\bin\\candle.exe";
string BundlePath = "C:\\Solution Directory\\Bundle.wxs";
string wixObjPathToSave = "C:\\Solution Directory\\Bundle.wxs";
ProcessStartInfo processStartInfo = new ProcessStartInfo("cmd.exe"); 
processStartInfo.WindowStyle = ProcessWindowStyle.Normal;
processStartInfo.Arguments ="/k \"" + candlePath + "\" " +BundlePath + " " +wixObjPathToSave;

[当我像上面那样传递参数时，进程正在接受参数，但是Candle.exe给出错误，因为我没有给bundlePath和wixobjPathToSave提供双引号，所以无法将'C：\ Solution'识别为内部或外部命令] >

processStartInfo.Arguments ="/k \"" + candlePath + "\" \"" +BundlePath + "\" \"" + wixObjPathToSave +"\"";
当我传递上面的参数时，该过程给出错误，即'C：\ Program'无法识别为内部或外部命令。

我做错了什么？

string CandlePath =“ C：\\ Program Files（x86）\\ WiX Toolset v3.11 \\ bin \\ candle.exe”;字符串BundlePath =“ C：\\ Solution Directory \\ Bundle.wxs”;字符串wixObjPathToSave =“ C：\\ Solution Directory \\ Bundle ....

Answer 1

我知道了答案