已解决
CONCAT((DATEDIFF(Minute,START_DTTM,END_DTTM)/60),'h:',
(DATEDIFF(Minute,START_DTTM,END_DTTM)%60) 'm') AS TotalTimeMissing
产生TotalTimeMissing。5小时13分
________
我试图在两个特定的日期之间返回一个时间戳值,以计算出一个包丢失和它被找到之间的时间。
EDIT: 代码已经更新,加入了Sami的代码。我还添加了额外的代码,这些代码是我从原始代码中排除的。
这是目前的代码。
USE PACKAGE
GO
SELECT
dp.LEGACY_ID
,dp.SURNAME
,dp.FORENAME
,dp.ETHNICITY_DESCRIPTION
,dp.BIRTH_DTTM
,DATEDIFF(YY, dp.BIRTH_DTTM, GETDATE()) -
CASE
WHEN RIGHT(CONVERT(VARCHAR(6), GETDATE(), 12), 4) >=
RIGHT(CONVERT(VARCHAR(6), dp.BIRTH_DTTM, 12), 4)
THEN 0
ELSE 1
END AS [Current Age]
--^Precise age calc due to potential LL inaccuracy
,mp.DIM_PERSON_ID
,mp.MISSING_STATUS
,mp.START_DTTM
,mp.END_DTTM
,dp.LEGACY_ID
,mp.RETURN_INT_OFFERED
,mp.RETURN_INT_ACCEPTED
,mp.RETURN_INT_DATE
FROM C_S.FACT_MISSING_PACKAGE AS mp
JOIN C_S.FACT_MISSING_PACKAGE AS dp ON mp.DIM_PERSON_ID = dp.DIM_PERSON_ID
WHERE CAST (mp.START_DTTM AS DATE)
BETWEEN DATEADD(YY, -1, CAST (GETDATE() AS DATE)) AND CAST (GETDATE() AS DATE)
--^Displays all records within exactly 1 year of run date
UNION (SELECT CONCAT(Value / 3600 / 24,
' Days ',
RIGHT(CONCAT('00', Value / 3600 % 24), 2),
':',
RIGHT(CONCAT('00', Value / 60 % 60), 2),
':',
RIGHT(CONCAT('00',Value % 3600 % 60), 2)
) AS TotalTimeMissing
FROM
(
SELECT mp.DIM_PERSON_ID, DATEDIFF(Second, mp.START_DTTM, mp.END_DTTM) Value
FROM C_S.FACT_MISSING_PACKAGE AS mp
) T(Value))
ORDER BY START_DTTM ASC;
萨米帮我完成了大部分的工作 但当我运行上面的代码时,我发现UNION和T出现了错误,T没有说明所需的列数。为了解决这个问题,我试着把最初一轮的SELECT列放到(SELECT CONCAT()语句中,但它会产生错误,所以在如何解决这个问题时,我有点不知所措?
我需要将这些列全部返回,并在最后增加一列作为TotalTimeMissing
谢谢你
你可以先用以下方法计算出分钟的差异 DATEDIFF
函数,然后计算小时和天,知道1小时是60分钟,1天是1440分钟。
请注意 DATEDIFF
在SQL Server中工作。
这个函数返回指定数据部分的计数(作为一个有符号的整数值)。边界 在指定的startdate和enddate之间交叉。
所以:
DATEDIFF(day, '2020-01-13 23:59:58', '2020-01-14 00:00:08')
将返回1,即使相差只有几秒,因为给定的时间间隔跨越了一天的边界(午夜)。
这就是为什么你不应该使用 DATEDIFF(day, ...)
这里却用 DATEDIFF(minute, ...)
或 DATEDIFF(second, ...)
并根据总的经过分钟或秒数计算出小时和天数。
我将使用 CROSS APPLY
我还使用了整数除法,以避免多次输入长表达式。/
这里摒弃了小数部分,例如:. 200 / 60 = 3
.
Total days = total minutes / 1440 (discard fractional part)
Total hours = total minutes / 60 (discard fractional part)
但是,我们不需要 总 小时,我们需要的是总天数后剩余的小时,所以我们需要取模24。
Hours = Total hours % 24
对于最后的分钟,我们只需要总天数和总小时数之后剩余的分钟,因此,我们需要的是
Minutes = total minutes mod 60.
的疑问。
SELECT
dp.LEGACY_ID
,dp.SURNAME
,dp.FORENAME
,mp.DIM_PERSON_ID
,mp.MISSING_STATUS
,mp.START_DTTM
,mp.END_DTTM
,dp.LEGACY_ID
,STR(DiffMinutes / 1440) + ':' + -- total days
STR(DiffMinutes / 60 % 24) + ':' + -- hours (0 .. 23)
STR(DiffMinutes % 60) AS TimeMissing -- minutes (0 .. 59)
FROM
MissingPackages AS mp
JOIN DIM_PERSON AS dp ON mp.DIM_PERSON_ID = dp.DIM_PERSON_ID
CROSS APPLY
(
SELECT DATEDIFF(minute, mp.START_DTTM, mp.END_DTTM) AS DiffMinutes
) AS A
ORDER BY START_DTTM ASC;
CONCAT(DATEDIFF(day, START_DT, END_DT), '-', DATEDIFF(hour, START_DT, END_DT), '-', DATEDIFF(minute, START_DT, END_DT)) AS TimeMissing
这是我们要找的东西吗?
CREATE TABLE MyData
(
StartDate DATETIME,
EndDate DATETIME
);
INSERT INTO MyData VALUES
('2017-01-01 00:00:00', '2018-01-02 00:25:01'),
('2017-01-01 00:00:00', '2018-01-01 00:00:00'),
('2017-01-02 12:00:09', '2017-01-02 12:00:30'),
('2017-01-01 02:00:00', '2017-01-01 03:30:30'),
('2017-01-01 00:00:00', '2017-01-03 00:30:30'),
('2017-12-31 23:59:59', '2018-01-01 00:00:01'),
('2017-12-31 23:59:01', '2018-01-01 00:00:01');
SELECT CONCAT(Value / 3600 / 24,
' Days ',
RIGHT(CONCAT('00', Value / 3600 % 24), 2),
':',
RIGHT(CONCAT('00', Value / 60 % 60), 2),
':',
RIGHT(CONCAT('00',Value % 3600 % 60), 2)
) TimeMissing
FROM
(
SELECT DATEDIFF(Second, StartDate, EndDate) Value
FROM MyData
) T(Value);
返回:
+-------------------+
| TimeMissing |
+-------------------+
| 366 Days 00:25:01 |
| 365 Days 00:00:00 |
| 0 Days 00:00:21 |
| 0 Days 01:30:30 |
| 2 Days 00:30:30 |
| 0 Days 00:00:02 |
| 0 Days 00:01:00 |
+-------------------+