如何在SwiftUI中展开到MainView

Question

我无法找到一种方法，而不从ViewB转到ContentView，而不在另一个NavigationView上方显示第二个NavigationView。

struct ContentView: View {
    var body: some View {
        NavigationView{
            VStack {
                Text("Go to ViewA")
                NavigationLink(destination: ViewA()) {Text("Go")}
            }.navigationBarTitle("ContentView")
        }
    }
}

struct ViewA: View {
   @Environment(\.presentationMode) var presentationMode
    var body: some View {
        VStack {
            Text("Go to ViewB")
            NavigationLink(destination: ViewB()) {Text("Go to B")}
            Text("Go back")
            Button(action: { self.presentationMode.wrappedValue.dismiss() }) {Text("Go to ContentView")}
        }.navigationBarTitle("ViewA")
    }
}

struct ViewB: View {
    @Environment(\.presentationMode) var presentationMode
    var body: some View {
        VStack {
            Text("Go Home")
            NavigationLink(destination: ContentView()) {Text("Go")}
            Text("Go back")
            Button(action: { self.presentationMode.wrappedValue.dismiss() }) {Text("Go to ViewB")}
        }.navigationBarTitle("ViewB")
    }
}

struct ContentView_Previews: PreviewProvider {
    static var previews: some View {
        ContentView()
    }
}

在“旧的” Swift中，我可以轻松地进行unwindSegue之类的操作>

@IBAction func unwindToVCMain(segue:UIStoryboardSegue) { }
}
并且像这样轻松地调用它>
performSegue(withIdentifier: "unwindToVcMain", sender: nil)
    

我无法找到一种方法，而不从ViewB转到ContentView，而无需在另一个NavigationView的顶部显示第二个NavigationView。 struct ContentView：视图{var body：some View {...

Answer 1

我也在寻找那种方法。我采用了两次调用self.presentationMode.wrappedValue.dismiss()的方法，但与取消事务的行为并不完全相同。