在下面找到json的回复......
{
"personalDetails": {
"Name ": " Taeyeon",
"Date Of Birth ": " 03/09/1989",
"Zodiac ": " Pisces"
},
"education": {
"High School ": " Jeonju Art High school ",
"University ": " -"
}
}
我的班级在这里
public class Biography
{
public personalDetails personalDetails { get; set; }
public education education { get; set; }
public work work { get; set; }
public personal personal { get; set; }
}
public class personalDetails
{
public string Name { get; set; }
public string DateBirth { get; set; }
public string Zodiac { get; set; }
}
public class education
{
public string HighSchool { get; set; }
public string University { get; set; }
}
然后我把代码:
Biography dataSet = JsonConvert.DeserializeObject<Biography>(e.Result);
由于Attribute有空间,它不起作用。我该怎么办?
尝试添加JsonProperty
属性。这对你有用。
[JsonProperty(PropertyName = "Date Of Birth ")]
public string DateBirth { get; set; }
[JsonProperty(PropertyName = "High School ")]
public string HighSchool { get; set; }
编辑
我看到你也有尾随空格,所以更新了上面的属性。对“名称”等做同样的事情。
将Json下载为字符串,并使用类似myString = myString.Replace(@“High School”,“HighSchool”)的内容。这是反序列化之前的步骤。
对某些人来说,这可能会有所帮助:
添加命名空间:using Newtonsoft.Json;
var jsonString = "{" +
"'personalDetails': {" +
"'Name ': 'Taeyeon'," +
"'Date Of Birth ': ' 03/09/1989'," +
"'Zodiac ': ' Pisces'," +
"}," +
"'education': {" +
"'High School ': ' Jeonju Art High school '," +
"'University ': ' -'," +
"}" +
"}";
var json = JsonConvert.DeserializeObject(jsonString);
return Ok(json);