我只想使用pyqt5在QTableWidget中单击第一列

问题描述 投票:0回答:1

我有2列QTableWidget。我只希望第一列可点击或可选,其他列则不可。

在下面的示例中,我只希望会话列是可单击的,而不是存档对象列

enter image description here

def _populateJobTW(self):
    #Populating ListWidget with data
    myDate = self.RundateEdit.date()
    SearchDate=myDate.toString('MM/dd/yyyy')
    mycursor=mydbhdb.cursor()
    mycursor.execute("""select "Archiving Session", "Archiving Object"||'('||"Variant"||')' from admirun where
     "Date of Archiving" = '{}' and "Archiving Object" != 'BC_XMB';""".format(SearchDate))
    result=mycursor.fetchall()
    self.JobTW.setRowCount(0)

   for row_number, row_data in enumerate(result):
        self.JobTW.insertRow(row_number)
        for column_number, data in enumerate(row_data):
            #item = self.cell("text")
            #item.setFlags(QtCore.Qt.ItemIsEnabled)
            self.JobTW.setItem(row_number, column_number, QTableWidgetItem(str(data)))
            ##############Make all column un selectable or other than the first column
            if column_number > 0:
                print(column_number)
                data1 = QTableWidgetItem(data)
                print(data1.text())
                data1.setFlags(data1.flags() | Qt.ItemIsSelectable)
                #data.setFlags(Qt.ItemIsEnabled | Qt.ItemIsSelectable)
def _cellClicked(self, row, col): 
    # Row and Col came directly from the click 
    item = self.JobTW.item(row, col) # Will assign the values 
    print("The session Nnumber is {} ".format(item.text()))
python pyqt pyqt5 qtablewidget
1个回答
0
投票

防止某些项目发出点击信号的一种可能的解决方案可能是重写mouseXEvents方法,从而覆盖默认行为,但这可能会引起问题,而一个简单的解决方案是在插槽中进行过滤:

def _cellClicked(self, row, col): 
    # Row and Col came directly from the click 
    if col == 0:
        item = self.JobTW.item(row, col) # Will assign the values 
        print("The session Nnumber is {} ".format(item.text()))

使用上面的方法,列仍处于选中状态,如果您不希望出现这种情况,则可以使用委托:

class NonSelectableDelegate(QStyledItemDelegate):
    def editorEvent(self, event, model, option, index):
        return index.column() != 0
delegate = NonSelectableDelegate(self.JobTW)
self.JobTW.setItemDelegate(delegate)
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