如果 A 包含数组 B 中的值，如何从数组 A 中删除值

Question

在栏 10514 上出现错误：

在“array.get()”函数中。索引 46 超出范围，数组大小为 45。

我无法解决原因。此代码的目的是从数组（numbersWHOLE 和numbersHALF）中删除数组（numbersBIG 和numbersBIGhalf）中的一组值。

问题所在的代码：

//@version=5
indicator("snippet", overlay=true, max_lines_count = 500, max_bars_back = 500)


TRange = 1.2700
BRange =  1.2205
ArrFreq = 100*syminfo.mintick
BRange00 = 1.2200
bigArrFreq = 1000*syminfo.mintick
BRangeBigHALF = 1.2250

var numbersWHOLE=array.new_float(0)
var numbersHALF=array.new_float(0)
var numbersBIG=array.new_float(0)
var numbersBIGhalf=array.new_float(0)

if barstate.islast and timeframe.isintraday
    for i = BRange00 to TRange by bigArrFreq
        array.push(numbersBIG,i)
    for i = BRangeBigHALF to TRange by bigArrFreq
        array.push(numbersBIGhalf,i)
    for i = BRange to TRange by ArrFreq
        array.push(numbersHALF,i)

    for i = BRange00 to TRange by ArrFreq
        //if array.indexof(numbersBIG,i) != array.get(numbersWHOLE,i)
        array.push(numbersWHOLE,i)

    for i = 0 to (array.size(numbersWHOLE) == 0 ? na : array.size(numbersWHOLE) - 1)
        ju = numbersWHOLE.get(i)   
        if numbersBIG.includes(ju)            
            //label.new(bar_index-i*2,low,str.tostring(array.get(numbersHALF,i)))
            numbersWHOLE.remove(i)
    for i = 0 to array.size(numbersHALF) - 1        
        line.new(bar_index - 20, array.get(numbersHALF,i),bar_index + 20,  array.get(numbersHALF,i), style = line.style_dashed, color = color.red, width = 1) //, extend = extend.both
    for i = 0 to array.size(numbersWHOLE) - 1        
        line.new(bar_index - 20, array.get(numbersWHOLE,i),bar_index + 20,  array.get(numbersWHOLE,i), style = line.style_dashed, color = color.red, width = 1) //, extend = extend.both
    
    for i = 0 to array.size(numbersBIGhalf) - 1
        line.new(bar_index - 400, array.get(numbersBIGhalf,i),bar_index + 100,  array.get(numbersBIGhalf,i), style = line.style_dashed, color = color.white, width = 1, extend = extend.both) //, extend = extend.both
    for i = 0 to array.size(numbersBIG) - 1
        line.new(bar_index - 400, array.get(numbersBIG,i),bar_index + 100,  array.get(numbersBIG,i), style = line.style_dashed, color = color.white, width = 1, extend = extend.both) //, extend = extend.both

我尝试了... in , while 的多种表达变化，但仍然无法让这个想法发挥作用。

Answer 1

这里是一个使用

array.includes()

、

array.indexof()

和

array.remove()

函数的示例。

//@version=5
indicator("snippet", overlay=true)

test_arr_1 = array.from(1.0, 1.1, 1.2, 1.3, 1.4, 1.5, 1.6, 1.7, 1.8, 1.9, 2.0)
test_arr_2 = array.from(1.0, 1.05, 1.1, 1.15, 1.2, 1.25, 1.3, 1.35, 1.4, 1.45, 1.5, 1.55, 1.6, 1.65, 1.7, 1.75, 1.8, 1.85, 1.9, 1.95, 2.0)
num_to_remove_arr = array.from(1.1, 1.8)

s1 = "------   Before   ------" + "\n" +
     "test_arr_1: " + str.tostring(test_arr_1) + "\n" + 
     "test_arr_2: " + str.tostring(test_arr_2) + "\n" + 
     "num_to_remove_arr: " + str.tostring(num_to_remove_arr) + "\n"

len = array.size(num_to_remove_arr)

if (len > 0)
    for i = 0 to len - 1
        num_to_remove = array.get(num_to_remove_arr, i)

        if (array.includes(test_arr_1, num_to_remove))
            idx = array.indexof(test_arr_1, num_to_remove)
            array.remove(test_arr_1, idx)

        if (array.includes(test_arr_2, num_to_remove))
            idx = array.indexof(test_arr_2, num_to_remove)
            array.remove(test_arr_2, idx)

s2 = "------   After   ------" + "\n" +
     "test_arr_1: " + str.tostring(test_arr_1) + "\n" + 
     "test_arr_2: " + str.tostring(test_arr_2) + "\n" + 
     "num_to_remove_arr: " + str.tostring(num_to_remove_arr) + "\n"

s = s1 + s2

if barstate.islast
    label.new(bar_index, high, s, textcolor=color.white)