使用C#创建IEnumerable >对象?

问题描述 投票:29回答:5

出于测试目的,我需要使用以下示例键值对创建IEnumerable<KeyValuePair<string, string>>对象:

Key = Name | Value : John
Key = City | Value : NY

最简单的方法是什么?

c# .net ienumerable keyvaluepair
5个回答
56
投票

任何:

values = new Dictionary<string,string> { {"Name", "John"}, {"City", "NY"} };

values = new [] {
      new KeyValuePair<string,string>("Name","John"),
      new KeyValuePair<string,string>("City","NY")
    };

或:

values = (new[] {
      new {Key = "Name", Value = "John"},
      new {Key = "City", Value = "NY"}
   }).ToDictionary(x => x.Key, x => x.Value);

8
投票

[Dictionary<string, string>实现IEnumerable<KeyValuePair<string,string>>


5
投票
var List = new List<KeyValuePair<String, String>> { 
  new KeyValuePair<String, String>("Name", "John"), 
  new KeyValuePair<String, String>("City" , "NY")
 };

1
投票
Dictionary<string,string> testDict = new Dictionary<string,string>(2);
testDict.Add("Name","John");
testDict.Add("City","NY");

是您的意思,还是还有其他意思?


1
投票

您可以简单地将Dictionary<K, V>分配给IEnumerable<KeyValuePair<K, V>>

IEnumerable<KeyValuePair<string, string>> kvp = new Dictionary<string, string>();

如果不起作用,可以尝试-

IDictionary<string, string> dictionary = new Dictionary<string, string>();
            IEnumerable<KeyValuePair<string, string>> kvp = dictionary.Select((pair) => pair);
© www.soinside.com 2019 - 2024. All rights reserved.