我有2个多维数组,我想获得第一个数组,其中数组1中的[file]
键的值等于数组2中的[folder_name]
键的值
$arr1 = [
[
'is_dir' => '1',
'file' => 'hello member',
'file_lcase' => 'hello member',
'date' => '1550733362',
'size' => '0',
'permissions' => '',
'extension' => 'dir',
],
[
'is_dir' => '1',
'file' => 'in in test',
'file_lcase' => 'in in test',
'date' => '1550730845',
'size' => '0',
'permissions' => '',
'extension' => 'dir',
]
];
$arr2 = [
[
'dic_id' => '64',
'folder_name' => 'hello member',
'share_with' => '11',
],
[
'dic_id' => '65',
'folder_name' => 'hello inside',
'share_with' => '11',
],
[
'dic_id' => '66',
'folder_name' => 'in in test',
'share_with' => '11',
],
];
我试过循环2个数组并获得一个数组,但它没有成功。
我们可以在彼此内部迭代两个数组,以检查我们是否匹配。
请注意,这仅显示第一场比赛。如果要保留所有匹配项,则应使用另一个帮助程序array
来存储与第二个数组匹配的第一个数组值。
foreach ($array1 as $key => $value) {
foreach ($array2 as $id => $item) {
if($value['file'] == $item['folder_name']){
// we have a match so we print out the first array element
print_r($array1[$key]);
break;
}
}
}
为避免出现时间复杂度为O(n²)的双循环,您可以先创建一组“folder_name”值(作为键),然后使用它来过滤第一个数组。这两个操作都具有O(n)的时间复杂度,对于较大的阵列来说肯定更有效:
$result = [];
$set = array_flip(array_column($arr2, "folder_name"));
foreach ($arr1 as $elem) {
if (isset($set[$elem["file"]])) $result[] = $elem;
}
$result
将具有符合要求的$arr1
元素。
$arr1 = array();
$arr2 = array();
$arr3 = array();
$arr1[] = array('is_dir'=>'1','file'=>'hello member','file_lcase'=>'hello member','date'=>'1550733362','size'=>'0','permissions'=>'','extension'=>'dir');
$arr1[] = array('is_dir'=>'1','file'=>'in in test','file_lcase'=>'in in test','date'=>'1550730845','size'=>'0','permissions'=>'','extension'=>'dir');
$arr2[] = array('dic_id'=>'64','folder_name'=>'hello member','share_with'=>'11');
$arr2[] = array('dic_id'=>'65','folder_name'=>'hello member','share_with'=>'11');
$arr2[] = array('dic_id'=>'66','folder_name'=>'in in test','share_with'=>'11');
foreach($arr1 as $a){
foreach($arr2 as $a2){
if($a['file'] == $a2['folder_name']){
$arr3[]=$a;
}
}
}
$arr3 = array_map("unserialize", array_unique(array_map("serialize", $arr3))); // remove duplicates
var_dump($arr3);
$ arr3包含结果数组。