无法使用时间戳查询数据库

问题描述 投票:0回答:1

我有这张桌子

user_authentication_token (
    token_id uuid,
    user_id uuid,
    email text,
    expiration_time timestamp,
    is_sign_up boolean,
    PRIMARY KEY ((token_id, user_id, email, expiration_time))

我在表格中有这些数据

token_id                             | user_id                              | email                   | expiration_time                 | is_sign_up
--------------------------------------+--------------------------------------+-------------------------+---------------------------------+------------
 98b0456a-05b2-4aca-a6c7-6a1f382e19aa | b284d51d-efbb-4204-b342-a2486029a5c5 | [email protected] | 2018-09-01 09:40:59.634000+0000 |       True

但我无法查询它。

select * from user_authentication_token where token_id=98b0456a-05b2-4aca-a6c7-6a1f382e19aa and user_id=b284d51d-efbb-4204-b342-a2486029a5c5 and email='[email protected]' and expiration_time='2018-09-01 09:40:59.634000+0000';

错误 - InvalidRequest: Error from server: code=2200 [Invalid query] message="Unable to coerce '2018-09-01 09:40:59.634000+0000' to a formatted date (long)"

我究竟做错了什么?

我使用Cassandra Java Datastax驱动程序和以下代码插入行

def insertValues(tableName:String, model:UserToken):Insert = {
    QueryBuilder.insertInto(tableName).value("token_id",model.tokenId) 
      .value("email",model.email)
      .value("user_id",model.userId)
      .value("expiration_time",model.expirationTime.getMillis())
      .value("is_sign_up",model.isSignUp)
      .ifNotExists(); }}

有趣的是,时间戳存储为long,但cqlsh以可读格式显示。可能我需要再次将它转换为long但我该怎么办呢?

cassandra-3.0
1个回答
0
投票

您的时间戳应该包括超过毫秒的任何内容:

select * from user_authentication_token
where token_id=98b0456a-05b2-4aca-a6c7-6a1f382e19aa
and user_id=b284d51d-efbb-4204-b342-a2486029a5c5
and email='[email protected]'
and expiration_time='2018-09-01 09:40:59.634+0000'; // removed extra precision

更新:添加了下面Manu Chadha发现的时区偏移量。

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