我有一个包含元素的数组,如下所示。我需要对数组进行部分排序,其中“ fix === 1”元素需要保留在开始/顶部,而无需任何排序,而排序将应用于条件为“ fix ====”的jobDueDate数组元素0“
我把这个结果放在开始/顶部的结果是[[fix列中,但是对“ fix === 1进行了排序,这不是必需的this.data = _.orderBy(this.data,['fix','jobDueDate'],['desc','asc']);
[
{
"id": 6060,
"jobNumber": 1878,
"jobDueDate": "2018-02-07T00:00:00",
"fix": 1
},
{
"id": 5337,
"jobNumber": 1836,
"jobDueDate": "2018-02-05T00:00:00",
"fix": 1
},
{
"id": 5702,
"jobNumber": 1863,
"jobDueDate": "2018-02-06T00:00:00",
"fix": 1
},
{
"id": 32583,
"jobNumber": 1611,
"jobDueDate": "1753-01-01T00:00:00",
"fix": 0
},
{
"id": 33403,
"jobNumber": 1932,
"jobDueDate": "2008-01-28T00:00:00",
"fix": 0
},
{
"id": 29481,
"jobNumber": 2741,
"jobDueDate": "2018-02-03T00:00:00",
"fix": 0
},
{
"id": 278,
"jobNumber": 1541,
"jobDueDate": "2018-02-05T00:00:00",
"fix": 0
},
{
"id": 5331,
"jobNumber": 1836,
"jobDueDate": "2018-02-05T00:00:00",
"fix": 0
},
{
"id": 5708,
"jobNumber": 1863,
"jobDueDate": "2018-02-06T00:00:00",
"fix": 0
},
{
"id": 6066,
"jobNumber": 1878,
"jobDueDate": "2018-02-07T00:00:00",
"fix": 0
},
{
"id": 5193,
"jobNumber": 1825,
"jobDueDate": "2018-02-08T00:00:00",
"fix": 0
}
]
_.sortBy(input, (o) => o.fix == 1 ? 0 : o.jobDueDate);