Google上的操作的登录方法存在问题

Question

我正在尝试使用谷歌登录方法为我的AoG，为我的用户提供更多的自定义体验，并将存储一些用户的数据，以便我可以提供更多相关的答案。我正在使用dailogflow.After调用登录我得到这个错误

。

app.intent('Default Welcome Intent',(conv)=>{
 
  conv.ask(`HIIIIIIIIIIIIIIIIIIIIIIIIIII`);
 
});
app.intent('ask_for_sign_in', (conv) => {
  conv.ask(new SignIn(`to get sign in details`));
  
});

app.intent('ask_for_sign_in_confirmation', (conv, params, signin) => {
  if (signin.status !== 'OK') {
    return conv.ask('You need to sign in before using the app.');
  }
  const payload = conv.user.profile.payload
  
    conv.ask(`I got your account details, ${payload.name}. What do you want to do next?`)
  const access = conv.user.access.token;
  
  db.collection("user").doc(access).set({
    name:"name",
    name2 : conv.user.access.name,
  }).then(()=>{
            conv.close(`document successfully written`);
            return;
  }).catch((e)=>{
    conv.close(`error writing document ${e}`);
  })
  // possibly do something with access token
  return conv.ask('Great! Thanks for signing in.');
});

Answer 1

app.intent('Start Signin', conv => {
  conv.ask(`siging you in`);
  conv.ask(new SignIn('To get your account details'))
})
app.intent('Default Welcome Intent',(conv)=>{
  conv.ask(`hi`);
})
// Create a Dialogflow intent with the `actions_intent_SIGN_IN` event.
app.intent('Get Signin', (conv, params, signin) => {
  if (signin.status === 'OK') {
    const payload = conv.user.profile.payload
    const {email} = conv.user;
    conv.ask(`I got your account details, ${payload.name}.and ${email} What do you want to do next?`)
    db.collection(`user`).doc(email).set({
      name:"some name",
    }).then(()=>{
          conv.ask(`success`);
          return;
    }).catch((e)=>{
        conv.close(`unscess ${e}`);
    })
  } else {
    conv.ask(`I won't be able to save your data, but what do you want to do next?`)
  }
})

这个代码将完美地工作，如果像我这样的人想要存储用户的数据，以便您可以在需要时提供相关信息，它在模拟器上工作也不用担心，并且不要忘记在dailogflow中添加clientID app=dailogflow({debug:true,clientID:"your clientID"})并从谷歌模块{dailogflow,signIn}=require("actions-on-google")上的动作获取signIn方法..