在mobx-state-tree中从同一模型的另一个动作中调用一个动作的良好实践是什么？

Question

我正在尝试将多个函数包装在一个函数中。

我有这样的模型：

const CookModel = types.actions(self =>({
  talkToSousChefs:() => {
    // talk to sous-chefs
  },
  talkToWaiters: () => {
    // business logic
  },
  talkToVendors: () => {
    // business logic
  },
  runTalkRoutine: () => {
    // current code

    const root = getRoot<typeof CookModel>(self)

    root.talkToSousChefs()
    root.talkToVendors()
    root.talkToWaiters()

    // what's the best practice?
  }
}))

将这些动作包装在runTalkRoutine中的最佳方法是什么？

Answer 1

  runTalkRoutine: () => {
    self.talkToSousChefs()
    self.talkToVendors()
    self.talkToWaiters()
  }

如果您有任何异步操作，则可以使用yield

如果要自动完成，可以将runTalkRoutine移动到另一个动作块
const CookModel = types.actions(self =>({
  talkToSousChefs:() => {
    // talk to sous-chefs
  },
  talkToWaiters: () => {
    // business logic
  },
  talkToVendors: () => {
    // business logic
  }
})).actions(self => ({
  runTalkRoutine: () => {
    // here you will have autocomplete on self
    self.talkToSousChefs()
    self.talkToVendors()
    self.talkToWaiters()
  }
}))