从外部文件在自己的运行空间中显示 wpf 对话框

Question

我有这个概念验证的 powershell 脚本，它将以其当前的形式工作，并将显示一个空白对话框，但以 wpf-ui 库为主题。

如果我将 $reader = (New-Object System.Xml.XmlNodeReader $xaml) 更改为 $reader = (New-Object System.Xml.XmlNodeReader $xaml2) 那么它会添加与 $xaml 相同的 xaml 代码，但来自文件它不会打开对话框。

我尝试了各种方法让它发挥作用，但似乎不明白为什么。

$Global:syncHash = [hashtable]::Synchronized(@{})
$newRunspace = [runspacefactory]::CreateRunspace()
$newRunspace.ApartmentState = "STA"
$newRunspace.ThreadOptions = "ReuseThread"
$newRunspace.Open()
$newRunspace.SessionStateProxy.SetVariable("syncHash", $syncHash)

$Global:Current_Folder = Split-Path $MyInvocation.MyCommand.Path

Add-Type -Path "$Current_Folder\Wpf.Ui.dll"
Add-Type -AssemblyName PresentationFramework

$psCmd = [PowerShell]::Create().AddScript({
        [xml]$xaml = @"
    <ui:FluentWindow xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
    xmlns:ui="http://schemas.lepo.co/wpfui/2022/xaml"
    xmlns:controls="clr-namespace:Wpf.Ui.Controls" Title="WPF UI" Width="800" Height="500" WindowStartupLocation="CenterScreen">
    <ui:FluentWindow.Resources>
        <ResourceDictionary>
            <ResourceDictionary.MergedDictionaries>
                <ResourceDictionary Source="pack://application:,,,/Wpf.Ui;component/Controls/FluentWindow/FluentWindow.xaml" />
                <ResourceDictionary Source="pack://application:,,,/Wpf.Ui;component/Controls/TitleBar/TitleBar.xaml" />
                <ui:ThemesDictionary Theme="Dark" />
            </ResourceDictionary.MergedDictionaries>
        </ResourceDictionary>
    </ui:FluentWindow.Resources>
    <Grid>
        <ui:TitleBar Name="TitleBar" Title="Test App" Margin="0" ShowMaximize="False" ShowMinimize="False">
        </ui:TitleBar>
    </Grid>
</ui:FluentWindow>
"@
        function LoadXaml($filename) {
            $XamlLoader = New-Object System.Xml.XmlDocument
            $XamlLoader.Load($filename)
            return $XamlLoader
        }

        $xaml2 = LoadXaml "$Current_Folder\simplegui.xaml"

        $reader = (New-Object System.Xml.XmlNodeReader $xaml)
    
        $syncHash.Window = [Windows.Markup.XamlReader]::Load( $reader )

        $syncHash.Window.ShowDialog() | Out-Null
        $syncHash.Error = $Error
    })
$psCmd.Runspace = $newRunspace
$psCmd.BeginInvoke()

Answer 1

工作代码

$Global:syncHash = [hashtable]::Synchronized(@{})
$newRunspace = [runspacefactory]::CreateRunspace()
$newRunspace.ApartmentState = "STA"
$newRunspace.ThreadOptions = "ReuseThread"
$newRunspace.Open()
$newRunspace.SessionStateProxy.SetVariable("syncHash", $syncHash)

$Global:Current_Folder = Split-Path $MyInvocation.MyCommand.Path

Add-Type -Path "$Current_Folder\Wpf.Ui.dll"
Add-Type -AssemblyName PresentationFramework

$psCmd = [PowerShell]::Create().AddScript({

        param($FolderPath)

        function LoadXaml($filename) {
            $XamlLoader = New-Object System.Xml.XmlDocument
            $XamlLoader.Load($filename)
            return $XamlLoader
        }

      $xaml = LoadXaml "$FolderPath\simplegui.xaml"

      $reader = (New-Object System.Xml.XmlNodeReader $xaml)
    
     $syncHash.Window = [Windows.Markup.XamlReader]::Load( $reader )

        $syncHash.Window.ShowDialog() | Out-Null
        $syncHash.Error = $Error
    })
$psCmd.Runspace = $newRunspace
$psCmd.AddParameter("FolderPath", $Current_Folder)
$psCmd.BeginInvoke()