如何优化“再试一次!”我的猜谜游戏有特色吗?

问题描述 投票:0回答:1

我目前正在学习 Python 并根据 YouTube 上的教程开发一个简单的猜谜游戏。用户有 3 次机会猜一个词。这是教程中的代码:

secret_word = "Giraffe"
guess = " "
guess_count = 0
guess_limit = 3
out_of_guesses = False

while guess != secret_word and not (out_of_guesses):

    if guess_count < guess_limit:
        guess = input("Enter guess: ")
        guess_count += 1
    else:
        out_of_guesses = True

if out_of_guesses:
    print("Out of Guesses, YOU LOSE!")
else:
    print("You win!")

代码运行完美,但我想让游戏说“再试一次!”如果用户在猜完之前回答错误。这是我到目前为止的代码:

secret_word = "moon"
guess = " "
guess_count = 0
guess_limit = 3
out_of_guesses = False

while guess != secret_word and not (out_of_guesses):

    if guess_count < guess_limit:
        guess = input("What's the word?\n ")
        guess_count += 1

        if guess != secret_word and guess_count < guess_limit:
            print("Try again!")
        else:
            "You are right!"

    else:
        out_of_guesses = True

if out_of_guesses:
    print("Out of guesses u noob")
else:
    print("You are right!")

代码仍然有效。但是,我觉得代码太长并且包含不必要的元素。预先感谢您的帮助!

python
1个回答
0
投票

无需使用

out_of_gueseses
变量,您可以简单地创建它,以便在没有足够的猜测时让您的代码跳出 while 循环。

所以在这里:

while guess != secret_word:
    if guess_count < guess_limit:
        (...)
        if guess != secret_word and guess_count < guess_limit:
            print("Try again!")
        else:
            print("You are right!")
            break
    else:
        break
# exit loop
(...) other code

希望这有帮助!

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