我试图从“line”字符串中获取两个玩家值,并使用正则表达式将它们插入到player1和player2中。
try (BufferedReader in = new BufferedReader(new FileReader(file))) {
String line;
String player1;
String player2;
while ((line = in.readLine()) != null) {
Scanner input = new Scanner(line);
input.useDelimiter("(.* [a-z] )|\\sby ");
if(line.toLowerCase().contains("kill")) {
kill += 1;
//i would like to set the player1 and player2 here
}
}
}
我文件的片段(.txt):
13:37 Kill: 3 4 7: Oootsimo killed Dono da Bola by MOD_ROCKET_SPLASH
13:37 Item: 5 weapon_rocketlauncher
13:39 Item: 6 weapon_rocketlauncher
13:40 Item: 7 ammo_rockets
13:41 Item: 6 weapon_rocketlauncher
13:41 Item: 4 weapon_rocketlauncher
13:43 Kill: 2 5 6: Isgalamido killed Assasinu Credi by MOD_ROCKET
13:45 Kill: 1022 7 22: <world> killed Mal by MOD_TRIGGER_HURT
13:46 Kill: 4 3 7: Dono da Bola killed Oootsimo by MOD_ROCKET_SPLASH
13:46 Kill: 6 2 6: Zeh killed Isgalamido by MOD_ROCKET
我不知道您的所有要求,但尝试使用Regexp:
@Test
public void test()
{
String string = "13:46 Kill: 6 2 6: Zeh killed Isgalamido by MOD_ROCKET";
String regexp = "\\d+:\\d+ .*?([A-Za-z0-9]+) killed ([A-Za-z0-9]+).*?";
String player1 = null;
String player2 = null;
Pattern p = Pattern.compile(regexp);
Matcher m = p.matcher(string);
if (m.find())
{
player1 = m.group(1);
player2 = m.group(2);
}
assertEquals("Zeh", player1);
assertEquals("Isgalamido", player2);
}
说明:\ d + - 一个数字,一次或多次
。* - 任何字符,任意次。 '?'意思是'非贪婪',因此匹配以下表达式的字符不会过度
([A-Za-z0-9] +) - 捕获一次或多次'[]'内的字符范围
一旦我确认这就是你的意思,我会再次编辑我的答案