嵌套函数的打字稿定义

Question

我正在尝试为我的（nodejs）控制器函数创建类型，如下所示

export const registerUser = asyncWrap(async function(req:Request, res:Response, next:NextFunction) {
    res.status(200).json({ success: true});
})

并且上面的代码很好，但是我想创建一个类型，所以我可以停止为函数params提供类型，这有点多余

我尝试过的事情

type NormTyped = (fn:Promise<any>) => (req: Request, res: Response, next: NextFunction) => any;

export const registerUser:NormTyped = asyncWrap(async function(req, res, next) {
    res.status(200).json({ success: true});
})

但是它给我错误

Type '(...args: any) => Promise<any>' is not assignable to type 'NormTyped'.
  Type 'Promise<any>' is not assignable to type '(req: Request<ParamsDictionary, any, any, ParsedQs>,         res: Response<any>, next: NextFunction) => any'.
Type 'Promise<any>' provides no match for the signature '(req: Request<ParamsDictionary, any, any, ParsedQs>, res: Response<any>, next: NextFunction): any'.

这是我的asyncWrap的样子（以防万一）

const asyncWrap = (fn: (...args: any) => any) =>
function asyncHandlerWrap(...args: any){
    const fnReturn = fn(...args)
    const next = args[args.length-1]
    return Promise.resolve(fnReturn).catch(next)
}

Answer 1

[NormTyped应该是接受函数作为参数的函数。

type NormTyped = (fn: (req: Request, res: Response, next: NextFunction) => any) => Promise<any>;

const asyncWrap = (fn: (...args: any) => any) =>
function asyncHandlerWrap(...args: any){
    const fnReturn = fn(...args)
    const next = args[args.length-1]
    return Promise.resolve(fnReturn).catch(next)
}

export const registerUser: NormTyped = asyncWrap(async function(req: string, res, next) {
    res.status(200).json({ success: true});
})