val = 26
for n in range (0,101):
if n in val:
print(n,"is the value i am looking for")
break
else:
print(n)
我一直收到此错误:
TypeError: argument of type 'int' is not iterable
此功能有什么问题
n in val
检查值n
是否在可迭代的val
中。此处正确的检查是n == val