如何在Vue JS应用中优化/加快自动搜索的速度?

问题描述 投票:0回答:1

我们已经在大约1200个条目的数组上实现了搜索功能,带有6个过滤器和一个搜索关键字。当用户选择任何过滤器或键入关键字时,将执行“自动”搜索以过滤显示的结果。问题在于,过滤后的数组重新渲染的速度比预期的慢,导致在渲染内容时应用程序冻结了不到一秒钟的时间。我的问题是如何优化以下代码以带来更好的用户体验,即在键入搜索关键字或选择过滤器时,结果应快速显示或以不打断用户的方式显示?

[我们拥有的结构是一个父组件,其中包含2个子组件:一个是Search条,包括下拉列表形式的过滤器,另一个是SearchResultsList,每行呈现4个Bootstrap-Vue b-card,直到该列表已用尽。

在父级中,我们像这样渲染两个孩子:

<b-row
  class="pt-sm-4 p-sm-0 p-2 bg-white"
  no-gutters
>
  <b-col
    sm="12"
    class="px-sm-3 mb-4"
  >
    <!-- People Search Bar -->
    <practice-people-search
      :people="filteredPeopleByKeyword"
      @togglePracticePeopleFiltersEvent="onTogglePracticePeopleFiltersEvent"/>

    <!-- Practice People Search Results List -->
    <practice-people-search-results-list
      :people="filteredPeopleByKeyword"
      :show-practice-people-filters="showPracticePeopleFilters"/>
  </b-col>
</b-row>

[我们还有一个created钩子和一些computed properties,它们分别进行后端调用以获取数据并过滤传入的数组。我们首先使用默认过滤器和/或任何其他选定的过滤器过滤大型1200个条目的数组,然后在用户键入关键字时过滤新创建的数组,例如

computed: {
    ...mapState('practice', [
      'practicePeopleKeyword',
      'practicePeopleCurrentValue',
      'practicePeopleOfficesValue',
      'practicePeopleGroupsValue',
      'practicePeopleOMGsValue',
      'practicePeopleStatusValue',
      'practicePeoplePositionValue']),
    filteredPeopleByFilters () {
      let filteredPeopleByFiltersArray = []
      for (let i = 0; i < this.people.length; i++) {
        let person = this.people[i]

        let currentResult = (this.practicePeopleCurrentValue.length === 0 || this.practicePeopleCurrentValue.filter((v) => {
          let cr = true
          switch (v.Value) {
            case 0:
              cr = (person.practiceCurrent === 1) && (person.officeCurrent === 1) && (person.groupCurrent === 1)
              break
            case 1:
              cr = (person.practiceCurrent === 0) && (person.started === 1)
              break
            case 2:
              cr = (person.practiceCurrent === 1) && (person.officeCurrent === 0)
              break
            case 3:
              cr = (person.practiceCurrent === 1) && (person.groupCurrent === 0)
              break
            case 4:
              cr = (person.started === 0)
              break
          }
          return cr
        }).length !== 0)
        let officeResult = (this.practicePeopleOfficesValue.length === 0 || this.practicePeopleOfficesValue.filter((v) => { return v.Value === person.mo_ref }).length !== 0)
        let groupResult = (this.practicePeopleGroupsValue.length === 0 || this.practicePeopleGroupsValue.filter((v) => { return v.Value === person.gp_ref }).length !== 0)
        let omgResult = (this.practicePeopleOMGsValue.length === 0 || this.practicePeopleOMGsValue.filter((v) => { return v.Value === person.omg_ref }).length !== 0)
        let statusResult = (this.practicePeopleStatusValue.length === 0 || this.practicePeopleStatusValue.filter((v) => {
          return (v.Value === person.mk_ref) || (v.Value === person.md_type)
        }).length !== 0)
        let positionResult = (this.practicePeoplePositionValue.length === 0 || this.practicePeoplePositionValue.filter((v) => {
          return v.Value === person.ms_ref || ((v.Value === -2) && (person.isPE === 1))
        }).length !== 0)

        if (currentResult && officeResult && groupResult && omgResult & statusResult && positionResult) {
          filteredPeopleByFiltersArray.push(person)
        }
      }
      return filteredPeopleByFiltersArray
    },
    filteredPeopleByKeyword () {
      let filteredPeopleByKeywordArray = []
      for (let i = 0; i < this.filteredPeopleByFilters.length; i++) {
        let person = this.filteredPeopleByFilters[i]

        let searchKeywordResult = (this.practicePeopleKeyword === '' || person.psname.indexOf(this.practicePeopleKeyword) > -1)

        if (searchKeywordResult) {
          filteredPeopleByKeywordArray.push(person)
        }
      }
      return filteredPeopleByKeywordArray
    }
  }

practice-people-search组件中的代码具有计算出的属性,以了解已选择了哪些过滤器,并将其存储在Vuex中,而practice-people-search-results-list组件仅呈现输入的道具:people="filteredPeopleByKeyword"

我希望以上所述是有道理的,如果有人对如何加快搜索速度有什么想法,以避免或至少将故障最小化,将不胜感激。干杯

javascript performance search optimization vuejs2
1个回答
0
投票

过滤1200个元素应该不会引起注意。显示的代码或应用程序中的其他地方一定存在效率低下的问题。

确保每次更改filteredPeopleByFilters()时都不会调用practicePeopleKeyword,而仅当过滤器更改时才调用。您可以使用快速的临时console.log来完成此操作。与filteredPeopleByKeyword()相同-确保每次更新仅调用一次。

也在if (currentResult && officeResult && groupResult && omgResult & statusResult && positionResult)中,您也没有从短路中受益。更改为类似

    let currentResult = ...
    if (!currentResult) continue;
    let officeResult = ...
    if (!officeResult) continue;
    let groupResult = ...
    if (!groupResult) continue;
    ... etc ...

写更少的代码。使用内置函数通常可以加快JS代码的速度。

例如,尝试更换

filteredPeopleByKeyword () {
  let filteredPeopleByKeywordArray = []
  for (let i = 0; i < this.filteredPeopleByFilters.length; i++) {
    let person = this.filteredPeopleByFilters[i]

    let searchKeywordResult = (this.practicePeopleKeyword === '' || person.psname.indexOf(this.practicePeopleKeyword) > -1)

    if (searchKeywordResult) {
      filteredPeopleByKeywordArray.push(person)
    }
  }
  return filteredPeopleByKeywordArray
}

使用

filteredPeopleByKeyword () {
  return this.filteredPeopleByFilters.filter(
    person => person.psname.indexOf(this.practicePeopleKeyword) > -1
  )
}
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