UIAction Sheet在iPad上不起作用,但在模拟器中起作用

问题描述 投票:3回答:2

我有一个奇怪的问题。当我在模拟器上运行我的应用程序时,一切正常,但在设备上,某些代码仍然无法响应!我有一个UIActionSheet,在Simulator上看起来还不错,但是在设备上根本无法正常工作。它甚至可以在iPod上运行:

这是显示操作表的代码:

 UIActionSheet *DeleteAction = [[UIActionSheet alloc] initWithTitle:@"Select    Delete Option" delegate:self cancelButtonTitle:Nil destructiveButtonTitle:nil   otherButtonTitles:nil, nil];
[DeleteAction addButtonWithTitle:@"A"];
[DeleteAction addButtonWithTitle:@"B"];
[DeleteAction showInView:self.view];

并且我正在使用该委托作为操作表

-(void)actionSheet:(UIActionSheet *)actionSheet clickedButtonAtIndex:(NSInteger)buttonIndex{
if ([actionSheet buttonTitleAtIndex:buttonIndex] == @"A") {....}
if ([actionSheet buttonTitleAtIndex:buttonIndex] == @"B") {....}
}
xcode ipad ios-simulator uiactionsheet
2个回答
2
投票

我已经使用了此代码,并且工作正常。让我知道它是否显示操作表]

-(void)share {
    UIActionSheet *popupQuery = [[UIActionSheet alloc] initWithTitle:@"" delegate:self cancelButtonTitle:@"cancel" destructiveButtonTitle:nil otherButtonTitles:@"Email this Info",@"Tweet this Info",@"Share On Facebook", nil];
    popupQuery.actionSheetStyle = UIActionSheetStyleBlackOpaque;
    [popupQuery showInView:self.view];
    [popupQuery release];
}

-(void)actionSheet:(UIActionSheet *)actionSheet clickedButtonAtIndex:(NSInteger)buttonIndex {
    if (buttonIndex == 0) {
        [self emailinfo];
    } 
    if (buttonIndex == 1) {
        [self tweetinfo];
    }
    if (buttonIndex == 2) {
        [self shareonfacebook];
    }
    if (buttonIndex == 3) {

    }
}

2
投票

问题已解决。

 if ([[actionSheet buttonTitleAtIndex:buttonIndex]isEqualToString: @"A"]) {....}

这对我有用。

© www.soinside.com 2019 - 2024. All rights reserved.