对象序列化和IDisposable

Question

        public static  string SerializeObject<T>(T obj)
        {
           try
           {
              string xmlString = null;
              MemoryStream memoryStream = new MemoryStream();
              XmlSerializer xs = new XmlSerializer(typeof(T));
              XmlTextWriter xmlTextWriter = new XmlTextWriter(memoryStream, Encoding.UTF8);
              xs.Serialize(xmlTextWriter, obj);
              memoryStream = (MemoryStream)xmlTextWriter.BaseStream;
              xmlString = UTF8ByteArrayToString(memoryStream.ToArray());      return xmlString;
           }
           catch
           {
              return string.Empty;
           }
        }

这来自 - 链接

有没有办法在不需要重新分配内存流对象的情况下编写这个？ 难道不应该将其丢弃（包装在 using 块中）吗？使用然后重新分配的内存流是什么？

Answer 1

我也不理解内存流重新分配。这是我的重构版本。

public static string SerializeObject<T>(T obj) 
{ 
   try 
   { 
      using (MemoryStream ms = new MemoryStream()) 
      {
        XmlSerializer xs = new XmlSerializer(typeof(T)); 
        XmlTextWriter xwriter = new XmlTextWriter(ms, Encoding.UTF8); 
        xs.Serialize(xwriter, obj); 
        return UTF8ByteArrayToString(ms.ToArray());
      }
   } 
   catch 
   { 
      return string.Empty; 
   } 
} 

Answer 2

你是对的。您应该将流包装在 using 块中。并且在using块中使用变量时不允许重新赋值。甚至不需要进行序列化。你可以这样做：

public static string SerializeObject<T>(T obj)
{
    try
    {
         string xmlString = null;
         using (MemoryStream memoryStream = new MemoryStream())
         {
            XmlSerializer xs = new XmlSerializer(typeof(T));
            XmlTextWriter xmlTextWriter = new XmlTextWriter(memoryStream, Encoding.UTF8);
            xs.Serialize(xmlTextWriter, obj);
            xmlString = UTF8ByteArrayToString(memoryStream.ToArray()); 
            return xmlString;
        }
     }
     catch
     {
         return string.Empty;
     }
}

Answer 3

我会以与其他答案略有不同的方式重构此代码，以首先检查类型是否可序列化。无法通过使用约束来做到这一点（http://bit.ly/c2Hq4s），但无论如何你都可以轻松检查它。我只是省略了 using 并添加了 Final 只是为了表明您也可以在不使用 using 的情况下完成它。

    public static  string SerializeObject<T>(T obj)
    {
       if (!typeof(T).IsSerializable)
       {
           throw new ArgumentException("type is not serializable");
       }

       string xmlString = string.Empty;
       MemoryStream memoryStream = new MemoryStream();

       try
       {
          XmlSerializer xs = new XmlSerializer(typeof(T));
          XmlTextWriter xmlTextWriter = new XmlTextWriter(memoryStream, Encoding.UTF8);
          xs.Serialize(xmlTextWriter, obj);
          xmlString = UTF8ByteArrayToString(memoryStream.ToArray());      
       }
       catch // something useful here
       {
          // Do something useful here
       }
       finally
       {
          // Dispose of what you want here
       }

       return xmlString;
    }

Answer 4

    public static string SerializeObject<T>(T o)
    {
        string serializeObject = string.Empty;
        if (o != null)
        {
            try
            {
                using (MemoryStream ms = new MemoryStream())
                {
                    XmlSerializer xs = new XmlSerializer(typeof(T));
                    xs.Serialize(ms, o);
                    using (System.IO.StreamReader sr = new StreamReader(ms))
                    {
                        serializeObject = sr.CurrentEncoding.GetString(ms.ToArray());
                    }
                }
            }
            catch { }
        }
        return serializeObject;
    }

Answer 5