如何在Grails中的Quartz作业开始时运行一次函数,并在调用之间保持变量值?

问题描述 投票:1回答:1

我是Groovy和Grails(以及Java)的新手,我有一个Quartz调度程序工作(下面的代码),想知道

1.)如何在第一次调用作业时(或在应用程序启动时,例如在另一个文件中)执行一些初始化(检查数据库并初始化局部变量),但是如何在此作业中设置计数器变量?

2.)变量是否在调用作业之间保持其值?如果没有,我该怎么做?

class MyJob {
    static triggers = {
        simple repeatInterval: 1000l // execute job every 1 second
    }

    // These need to be initiated (with values from a DB) the first time the job is run:
    long myCounter1, myCounter2, myCounter3

    def execute() {

    if(first time job is run / application startup) {
    // get values for counters defined above, from DB
    }
    // else values should persist from last job run

    // Get stuff from database, passing in counter values

}

我正在使用Grails https://grails-plugins.github.io/grails-quartz/guide/introduction.html的Quartz插件,它使用Quartz Scheduler http://www.quartz-scheduler.org/documentation/2.4.0-SNAPSHOT/quick-start-guide.html

谢谢

java grails groovy quartz-scheduler
1个回答
1
投票

使用@PersistJobDataAfterExecution注释您的工作,并使用JobDataMap在执行之间存储/检索数据。

import org.quartz.*;

@PersistJobDataAfterExecution
public class ExampleJob {

    static triggers = {
        simple repeatInterval: 1000l // execute job every 1 second
    }

    @Override
    void execute(JobExecutionContext jobExecutionContext) throws JobExecutionException {
        JobDataMap jobDataMap = jobExecutionContext.jobDetails.jobDataMap
        Integer count = jobDataMap.get("count") ?: 0    
        jobDataMap.put("count", ++count)
    }
}
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