假设我有一个1497664242
的unix时间戳,它是Saturday, June 17, 2017 1:50:42 AM
我想找到表中所有在同一天内有时间戳的记录。
我尝试设置像1494979200
这样的时间戳,这是Saturday, June 17, 2017 12:00:00 AM
认为我可以使用当天的一般时间并拉出当天匹配的所有记录。
我试图从特定的日期循环,找到那天匹配的所有记录然后增加1天直到今天04/12/2019
$start_date = "05/17/2017";
while ($start_date != "04/12/2019") {
$timestamp = strtotime($start_date);
$sql_select = "SELECT * FROM table WHERE DATE(timestamp) = DATE(FROM_UNIXTIME($timestamp))";
$result_select = $GLOBALS['db']->query($sql_select);
while ($row = $result_select->fetch_array()) {
// will do stuff here
}
$start_date = date("m/d/Y", strtotime($start_date. "+1 day"));
}
如果您将时间戳转换为DATE,即2017-06-17以及数据库中的时间戳字段,那么您应该在当天获得任何行
现在我们知道列timestamp
实际上被定义为VARCHAR()你必须这样做
SELECT *
FROM table
WHERE DATE(FROM_UNIXTIME(timestamp)) = '$start_date';
所以对于你的实际代码
$start_date = "2017-05-17";
while ($start_date != "2019-04-12") {
$sql_select = "SELECT *
FROM table
WHERE DATE(FROM_UNIXTIME(timestamp)) = '$start_date'";
$result_select = $GLOBALS['db']->query($sql_select);
while ($row = $result_select->fetch_array()) {
// will do stuff here
}
$start_date = date("Y-m-d", strtotime($start_date. "+1 day"));
}
我不会像建议的那样在SQL查询中使用函数(DATE(FROM_UNIXTIME(timestamp))
),因为这会阻止SQL在timestamp列上使用索引。
我会在php(day's begin + end)中计算两个日期时间,如下所示:
$dt = new DateTime('@' . $timestamp); // Should take care about timezones if you need
$dt_begin = $dt->format('Y-m-d 00:00:00');
$dt_end = $dt->format('Y-m-d 23:59:59');
如果DB中的时间戳存储为整数:
SELECT
*
FROM
table
WHERE
timestamp BETWEEN UNIX_TIMESTAMP('$dt_begin') AND UNIX_TIMESTAMP('$dt_end')
如果DB中的时间戳存储为TIMESTAMP或DATETIME:
SELECT
*
FROM
table
WHERE
timestamp BETWEEN '$dt_begin' AND '$dt_end'