如何将字符串转换或类型转换为二进制整数？

Question

"11001001101000000100010101"

"00111000000011010000101011"

和

= 00001000000000000000000001

二进制表示。

"11001001101000000100010101" = > 0b11001001101000000100010101

"00111000000011010000101011" = > 0b00111000000011010000101011

两个字符串，但值看起来像二进制，我想Bitwise和运营商的两个二进制。

如何将字符串转换为二进制？

Answer 1

UInt和String都有init方法，在这里你可以给出数字的弧度（基数）。

let s1 = "11001001101000000100010101"
let s2 = "00111000000011010000101011"

if let binary1 = UInt(s1, radix: 2), let binary2 = UInt(s2, radix: 2) {
    let res = binary1 & binary2
    print(String(res, radix: 2))
}

产出

1000000000000000000001