如何改变QML对话框中回车键的行为?

问题描述 投票:2回答:1

下面的代码创建了一个对话框,在按 "Enter "键和按 "OK "键之间发生了不一致的行为。按 "回车 "键和按 "确定 "键之间的行为不一致。当改变一个字段时按下回车键,只有该字段被更新。当按下 "确定 "键时,两个字段都会被更新(首选)。如何覆盖回车键在这里做合理的事情?

我真正想要的是,如果回车键能在不关闭对话框的情况下将更新的字段送回应用程序,因为我想在对话框中控制一些东西。

视图.qml

import QtQuick 2.0
import QtQuick.Layouts 1.12
import QtQuick.Controls 2.12
import QtQuick.Window 2.12
import QtQuick.Dialogs 1.3


Item {
    Dialog {
        id: thedialog
        ColumnLayout {
            TextField {
                id: numberField
                onAccepted: {
                    backend.number = text
                }
            }
            TextField {
                id: textField
                onAccepted: {
                    backend.text = text
                }
            }
        }

        onButtonClicked: {
            backend.number = numberField.text
            backend.text = textField.text
        }

    }
    Button {
        text: "Show Dialog"
        onClicked: thedialog.open()
    }
}

main.py

import sys
from PySide2.QtCore import QObject, Signal, Property
from PySide2.QtWidgets import QApplication, QMainWindow
from PySide2.QtQuickWidgets import QQuickWidget

class Backend(QObject):

    def __init__(self):
        QObject.__init__(self)
        self._number = 0
        self._text = ""

    def getNumber(self):
        return self._number

    def setNumber(self, number):
        print(f"Setting number to: {number}")
        self._number = number
        self.notifyNumber.emit()

    notifyNumber = Signal()

    number = Property(float, getNumber, setNumber, notify=notifyNumber)

    def getText(self):
        return self._text

    def setText(self, text):
        print(f"Setting text to: {text}")
        self._text = text
        self.notifyText.emit()

    notifyText = Signal()

    text = Property(str, getText, setText, notify=notifyText)



if __name__ == '__main__':

    app = QApplication(sys.argv)
    window = QMainWindow()

    quick = QQuickWidget()
    backend = Backend()
    quick.rootContext().setContextProperty("backend", backend)
    quick.setSource("view.qml")

    window.setCentralWidget(quick)
    window.show()

    sys.exit(app.exec_())
python dialog qml pyqt5 pyside2
1个回答
2
投票

使用 附带密钥API:

import QtQuick 2.14
import QtQuick.Layouts 1.14
import QtQuick.Controls 2.14

ApplicationWindow {
    width: 800
    height: 600
    visible: true

    QtObject {
        id: backend
        property real number
        property string text
    }

    Dialog {
        id: thedialog

        function doSomeStuffBeforeClosingTheDialog() {
            backend.number = parseFloat(numberField.text)
            backend.text = textField.text
            // Remove this if you do not want the dialog to close
            accept()
        }

        ColumnLayout {
            TextField {
                id: numberField
                onAccepted: backend.number = text

                Keys.onReturnPressed: thedialog.doSomeStuffBeforeClosingTheDialog()
            }
            TextField {
                id: textField
                onAccepted: backend.text = text

                Keys.onReturnPressed: thedialog.doSomeStuffBeforeClosingTheDialog()
            }
        }
    }
    Button {
        text: "Show Dialog"
        onClicked: thedialog.open()
    }
}
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