使用日期和状态字段的mysql排序问题

问题描述 投票:0回答:1

需要根据日期和状态以最有效的方式订购某些项目/事件的想法。

目前我有以下查询。

select tevent.ID, tevent.ename, e_dates.edate, tevent.status, tevent.eactive  from tevent 
LEFT JOIN e_dates on tevent.ID=e_dates.EID) Where tevent.status <> 'delete' and tevent.eactive ='Y'  group by tevent.id order 
by (case when tevent.status = 'closed' and e_dates.edate >= curdate() then 0 
else 1 end), edates.edate desc

我使用了一个案例,但它按顺序排列了状态,然后是日期,这让人感到困惑。

以下是输出

+----+--------------+-----+-----------+
| ID |Edate           | Ename   | Status  | 
+----+--------------+-----+-----------+
|  2  | 2018-09-21    | Event2  | Closed  |
|  5  | 2018-09-15    | Event5  | Closed  | 
|  3  | 2018-12-12    | Event3  | Open    |
|  6  | 2018-10-25    | Event6  | Approved|
|  4  | 2018-10-25    | Event4  | Open    |
|  7  | 2018-10-15    | Event7  | Pending |
|  10 | 2018-10-01    | Event10 | Open    |
|  1  | 2018-09-30    | Event1  | Open    |
|  4  | 2018-09-30    | Event4  | Open    |
|  8  | 2018-09-01    | Event8  | Closed  |
|  11 | 2018-08-25    | Event11 | Closed  |
+----+--------------+-----+-----------+

编辑:我想要完成的是列出事件日期在事件发生之前的封闭事件。 IE(ID 2和ID 5)

但是希望ASC按时间顺序列出OPEN,APPROVED,PENDING的事件状态。

事件日期(edate)位于底部列出的当前日期(now())之后的已结束事件

例如:

   +----+--------------+-----+-----------+
    | ID |Edate           | Ename   | Status  | 
    +----+--------------+-----+-----------+
    |  2  | 2018-09-21    | Event2  | Closed  |
    |  5  | 2018-09-15    | Event5  | Closed  | 
    |  1  | 2018-09-30    | Event1  | Open    |*
    |  4  | 2018-09-30    | Event4  | Open    |*
    |  10 | 2018-10-01    | Event10 | Open    |*
    |  7  | 2018-10-15    | Event7  | Pending |*
    |  4  | 2018-10-25    | Event4  | Open    |*
    |  6  | 2018-10-25    | Event6  | Approved|*
    |  3  | 2018-12-12    | Event3  | Open    |*
    |  11 | 2018-08-25    | Event11 | Closed  |    
    |  8  | 2018-09-01    | Event8  | Closed  |
    +----+--------------+-----+-----------+
mysql sql-order-by
1个回答
1
投票

我觉得你几乎是对的。在case语句中需要三个选项 - 0表示顶部所有已关闭的选项,2表示底部所有已关闭的选项,1表示中间其他所有选项。然后删除日期上的desc以使每个部分内的日期升序,因此order by子句应如下所示

order by (
    case when tevent.status = 'closed' and e_dates.edate >= curdate() then 0 
    when tevent.status = 'closed' and e_dates.edate < curdate() then 2
    else 1 end
), edates.edate

或者你可以写同样的东西

order by (
    case when tevent.status = 'closed' 
        then case when e_dates.edate >= curdate() then 0 else 2 end
    else 1 end
), edates.edate
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