需要根据日期和状态以最有效的方式订购某些项目/事件的想法。
目前我有以下查询。
select tevent.ID, tevent.ename, e_dates.edate, tevent.status, tevent.eactive from tevent
LEFT JOIN e_dates on tevent.ID=e_dates.EID) Where tevent.status <> 'delete' and tevent.eactive ='Y' group by tevent.id order
by (case when tevent.status = 'closed' and e_dates.edate >= curdate() then 0
else 1 end), edates.edate desc
我使用了一个案例,但它按顺序排列了状态,然后是日期,这让人感到困惑。
以下是输出
+----+--------------+-----+-----------+
| ID |Edate | Ename | Status |
+----+--------------+-----+-----------+
| 2 | 2018-09-21 | Event2 | Closed |
| 5 | 2018-09-15 | Event5 | Closed |
| 3 | 2018-12-12 | Event3 | Open |
| 6 | 2018-10-25 | Event6 | Approved|
| 4 | 2018-10-25 | Event4 | Open |
| 7 | 2018-10-15 | Event7 | Pending |
| 10 | 2018-10-01 | Event10 | Open |
| 1 | 2018-09-30 | Event1 | Open |
| 4 | 2018-09-30 | Event4 | Open |
| 8 | 2018-09-01 | Event8 | Closed |
| 11 | 2018-08-25 | Event11 | Closed |
+----+--------------+-----+-----------+
编辑:我想要完成的是列出事件日期在事件发生之前的封闭事件。 IE(ID 2和ID 5)
但是希望ASC按时间顺序列出OPEN,APPROVED,PENDING的事件状态。
事件日期(edate)位于底部列出的当前日期(now())之后的已结束事件
例如:
+----+--------------+-----+-----------+
| ID |Edate | Ename | Status |
+----+--------------+-----+-----------+
| 2 | 2018-09-21 | Event2 | Closed |
| 5 | 2018-09-15 | Event5 | Closed |
| 1 | 2018-09-30 | Event1 | Open |*
| 4 | 2018-09-30 | Event4 | Open |*
| 10 | 2018-10-01 | Event10 | Open |*
| 7 | 2018-10-15 | Event7 | Pending |*
| 4 | 2018-10-25 | Event4 | Open |*
| 6 | 2018-10-25 | Event6 | Approved|*
| 3 | 2018-12-12 | Event3 | Open |*
| 11 | 2018-08-25 | Event11 | Closed |
| 8 | 2018-09-01 | Event8 | Closed |
+----+--------------+-----+-----------+
我觉得你几乎是对的。在case语句中需要三个选项 - 0表示顶部所有已关闭的选项,2表示底部所有已关闭的选项,1表示中间其他所有选项。然后删除日期上的desc以使每个部分内的日期升序,因此order by子句应如下所示
order by (
case when tevent.status = 'closed' and e_dates.edate >= curdate() then 0
when tevent.status = 'closed' and e_dates.edate < curdate() then 2
else 1 end
), edates.edate
或者你可以写同样的东西
order by (
case when tevent.status = 'closed'
then case when e_dates.edate >= curdate() then 0 else 2 end
else 1 end
), edates.edate