获取一个月中的第一个或最后一个星期五

问题描述 投票:0回答:13

我正在尝试编写这样的日历函数

function get_date($month, $year, $week, $day, $direction)
{
    ....
}

$week
是一个整数 (1, 2, 3...),$day 是一天 (Sun, Mon, ...) 或数字,以更简单的为准。方向有点混乱,因为它进行了不同的计算。

举个例子,我们打电话给

get_date(5, 2009, 1, 'Sun', 'forward');

它使用默认值,并获取五月的第一个星期日,即2009-05-03。如果我们打电话

get_date(5, 2009, 2, 'Sun', 'backward');

,它返回五月的第二个最后一个星期日,即 2009-05-24。

php datetime
13个回答
27
投票

与语言无关的版本:

要获取该月的第一天,请从该月的第一天开始:yyyy-mm-01。使用任何可用的函数来给出与星期几相对应的数字。从您要查找的日期减去该数字;例如,如果该月的第一天是星期三 (2),而您要查找星期五 (4),则从 4 中减去 2,剩下 2。如果答案是否定的,则添加 7。最后将其添加到第一个这个月;以我为例,第一个星期五将是第三个。

要获取该月的最后一个星期五,请找到下个月的第一个星期五并减去 7 天。


13
投票

也许可以做得更快......
这对代码来说非常有趣。

请注意,

$direction
为 1 表示向前,-1 表示向后,以简化操作:)
此外,
$day
周一的值从 1 开始,周日的值 7 结束。

function get_date($month, $year, $week, $day, $direction) {
  if($direction > 0)
    $startday = 1;
  else
    $startday = date('t', mktime(0, 0, 0, $month, 1, $year));

  $start = mktime(0, 0, 0, $month, $startday, $year);
  $weekday = date('N', $start);

  if($direction * $day >= $direction * $weekday)
    $offset = -$direction * 7;
  else
    $offset = 0;

  $offset += $direction * ($week * 7) + ($day - $weekday);
  return mktime(0, 0, 0, $month, $startday + $offset, $year);
}

我已经用几个例子对其进行了测试,似乎总是有效,但请务必仔细检查;)


12
投票

PHP 的内置时间函数使这一切变得简单。

http://php.net/manual/en/function.strtotime.php

// Get first Friday of next month.
$timestamp = strtotime('first fri of next month');

// Get second to last Friday of the current month.
$timestamp = strtotime('last fri of this month -7 days');

// Format a timestamp as a human-meaningful string.
$formattedDate = date('F j, Y', strtotime('first wed of last month'));

请注意,我们始终希望确保已定义与

strtotime
一起使用的正确时区,以便 PHP 了解在何处计算相对于机器认为其所在时区的时间戳。

date_default_timezone_set('America/New_York');
$formattedDate = date('F j, Y', strtotime('first wed of last month +1 week'));

8
投票

strtotime()可以帮助你。例如

<?php
$tsFirst = strtotime('2009-04-00 next friday');
$tsLast = strtotime('2009-05-01 last friday');
echo date(DATE_RFC850, $tsFirst), " | ", date(DATE_RFC850, $tsLast);
打印
2009 年 4 月 3 日星期五 00:00:00 CEST | 2009 年 4 月 24 日星期五 00:00:00 CEST


6
投票

无需计算或循环 - 使用 strtotime() 非常容易做到:

查找特定月份中特定日期的第 N 次或最后一次出现:

/////////////////////////////////////////////////////////////////
// Quick Code
/////////////////////////////////////////////////////////////////

// Convenience mapping.
$Names = array( 0=>"Sun", 1=>"Mon", 2=>"Tue", 3=>"Wed", 4=>"Thu", 5=>"Fri", 6=>"Sat" );

// Specify what we want
// In this example, the Second Monday of Next March
$tsInMonth = strtotime('March');
$Day = 1;
$Ord = 2;

// The actual calculations
$ThisMonthTS = strtotime( date("Y-m-01", $tsInMonth ) );
$NextMonthTS = strtotime( date("Y-m-01", strtotime("next month", $tsInMonth) ) );
$DateOfInterest = (-1 == $Ord) 
    ? strtotime( "last ".$Names[$Day], $NextMonthTS ) 
    : strtotime( $Names[$Day]." + ".($Ord-1)." weeks", $ThisMonthTS ); 


/////////////////////////////////////////////////////////////////
// Explanation
/////////////////////////////////////////////////////////////////

// Specify the month of which we are interested.
// You can use any timestamp inside that month, I'm using strtotime for convenience.
$tsInMonth = strtotime('March');

// The day of interest, ie: Friday.  
// It can be 0=Sunday through 6=Saturday (Like 'w' from date()).
$Day = 5;

// The occurrence of this day in which we are interested.  
// It can be 1, 2, 3, 4 for the first, second, third, and fourth occurrence of the day in question in the month in question.
// You can also use -1 to fine the LAST occurrence.  That will return the fifth occurrence if there is one, else the 4th.
$Ord = 3;

////////////////////////////////////////////////////////////////
// We now have all the specific values we need.
// The example values above specify the 3rd friday of next march
////////////////////////////////////////////////////////////////

// We need the day name that corresponds with our day number to pass to strtotime().
// This isn't really necessary = we could just specify the string in the first place, but for date calcs, you are more likely to have the day number than the string itself, so this is convenient.
$Names = array( 0=>"Sun", 1=>"Mon", 2=>"Tue", 3=>"Wed", 4=>"Thu", 5=>"Fri", 6=>"Sat" );

// Calculate the timestamp at midnight of the first of the month in question.
// Remember $tsInMonth is any date in that month.
$ThisMonthTS = strtotime( date("Y-m-01", $tsInMonth ) );

// Calculate the timestamp at midnight of the first of the FOLLOWING month.
// This will be used if we specify -1 for last occurrence.
$NextMonthTS = strtotime( date("Y-m-01", strtotime("next month", $tsInMonth) ) );

// Now we just format the values a bit and pass them to strtotime().
// To find the 1,2,3,4th occurrence, we work from the first of the month forward.
// For the last (-1) occurence,work we work back from the first occurrence of the following month.
$DateOfInterest = (-1 == $Ord) ?
    strtotime( "last ".$Names[$Day], $NextMonthTS ) : // The last occurrence of the day in this month.  Calculated as "last dayname" from the first of next month, which will be the last one in this month. 
    strtotime( $Names[$Day]." + ".($Ord-1)." weeks", $ThisMonthTS ); // From the first of this month, move to "next dayname" which will be the first occurrence, and then move ahead a week for as many additional occurrences as you need.

4
投票
echo date('Y-m-d',strtotime('last friday'));

2
投票

您可以使用 mktime 检索该月第一天的unix时间戳:

$firstOfMonth = mktime(0, 0, 0, $month, 1, $year);

当您知道某个月第一天的日期时,可以使用 date 轻松检索该日期的工作日:

$weekday = date("N", $firstOfMonth);

从那里开始就可以很容易地得到你想要的日期。


1
投票
function get_date($month, $year, $week, $day) {
    # $month, $year: current month to search in
    # $week: 0=1st, 1=2nd, 2=3rd, 3=4th, -1=last
    # $day:  0=mon, 1=tue, ..., 6=sun

    $startday=1; $delta=0;
    if ($week < 0) {
        $startday = date('t', mktime(0, 0, 0, $month, 1, $year)); # 28..31
        $delta=1;
    }
    $start  = mktime(0, 0, 0, $month, $startday, $year);
    $dstart = date('w', $start)-1; # last of the month falls on 0=mon,6=sun
    $offset=$day-$dstart; if ($offset<$delta){$offset+=7;}
    $newday=$startday+$offset+($week*7);
    return mktime(0, 0, 0, $month, $newday, $year);
}

这对我有用,并且基于与语言无关的版本:-) 只是太糟糕了,我需要做那个 delta 事情(因为如果该月的最后一天是想要的工作日,我们不需要减去 7)


1
投票

使用

DateTime
类可以非常优雅地完成同样的任务。

$time_zone = new DateTimeZone('Europe/Ljubljana');

$first_friday_of_this_month = new DateTime('first Friday of this month', $time_zone);
$last_friday_of_this_month = new DateTime('last Friday of this month', $time_zone);

echo $first_friday_of_this_month->format('Y-m-d');  # 2015-11-06
echo $last_friday_of_this_month->format('Y-m-d');  # 2015-11-27

0
投票

只需找出相关月份的第一天和最后一天(即2009年5月1日是星期五,2009年5月31日是星期日)我相信大多数PHP函数使用Monday=0,Sunday=6,因此星期五=4,所以你知道周日(6)-周五(4)=2,那么31-2=29,意味着这个月的最后一个周五是29号。对于第一个星期五,如果数字为负数,则加 7,如果数字为 0,则月份从星期五开始。


0
投票

这似乎每次都很完美;它接受提供的任何日期并返回该月最后一个星期五的日期,即使是该月的第 5 个星期五也是如此。

function get_last_friday_of_month($inDate) {
    $inDate = date('Y-m-24', strtotime($inDate));
    $last_friday = date('Y-m-d',strtotime($inDate.' next friday'));
    $next_friday = date('Y-m-d',strtotime($inDate.' next friday'));

    if(date('m', strtotime($last_friday)) === date('m', strtotime($next_friday))){
        $last_friday = $next_friday;
    }else{
        //
    }
    return $last_friday;
}

0
投票

以下是最快的解决方案,您可以在所有条件下使用。如果你稍微调整一下,你还可以获得一周中整天的数组。

function findDate($date, $week, $weekday){
    # $date is the date we are using to get the month and year which should be a datetime object
    # $week can be: 0 for first, 1 for second, 2 for third, 3 for fourth and -1 for last
    # $weekday can be: 1 for Monday, 2 for Tuesday, 3 for Wednesday, 4 for Thursday, 5 for Friday, 6 for Saturday and 7 for Sunday 

    $start = clone $date;
    $finish = clone $date;

    $start->modify('first day of this month');
    $finish->modify('last day of this month');
    $finish->modify('+1 day');

    $interval = DateInterval::createFromDateString('1 day');
    $period = new DatePeriod($start, $interval, $finish);

    foreach($period AS $date){
        $result[$date->format('N')][] = $date;
    }

    if($week == -1)
        return end($result[$weekday]);
    else
        return $result[$weekday][$week];
}


$date = DateTime::createFromFormat('d/m/Y', '25/12/2016');

# find the third Wednesday in December 2016
$result = findDate($date, 2, 3); 
echo $result->format('d/m/Y');

我希望这有帮助。

如果您需要任何进一步的信息,请告诉我。 ;)


0
投票

这是我在项目中取得了一些成功的代码部分

$fromLastDay    =  array( '5' => 0, '4' => 6, '3' => 5, '2' => 4, '1' => 3, '0' => 2, '6' => 1 );
$to1stFriday    =  array( '5' => 0, '4' => 1, '3' => 2, '2' => 3, '1' => 4, '0' => 5, '6' => 6 );
$curr1stFriday  = 1 + ( $to1stFriday[date("w", strtotime(date('Y-m-1')))]);
$currLastFriday = date('t') - $fromLastDay[date('w', strtotime(date('Y-m-t')))];

## Check for Friday
if ( date("w") != 5 ) { 
    echo "Check For FRIDAY execution: ".date("l")." the ". date("d")." is NOT a Friday in ".date("F, Y").".\n";
} else {
    ## It's Friday, do something...
}

## Check for the First Friday
if (date('j') != $curr1stFriday) { 
    echo "Check For FRIDAY execution: ".date("l")." the ". date("d")." is NOT the First Friday of ".date("F, Y").".\n";
} else {
    ## First Friday, do something...
}

## Check for the Last Friday
if (date('j') != $currLastFriday) {
    echo "Check For FRIDAY execution: ".date("l")." the ". date("d")." is NOT the Last Friday of ".date("F, Y").".\n";
} else {
    ## Last Friday, do something...
}
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