导出redux存储状态的接口

Question

开始制作redux模块后，我创建了以下文件：

//state.tsx
export default interface State {
  readonly user: any;
  readonly isLoggedIn: boolean;
}


//types.tsx
export default {
  REQUEST: 'authentication/REQUEST',
  SUCCESS: 'authentication/SUCCESS',
  FAILURE: 'authentication/FAILURE',
  LOGOUT: 'authentication/LOGOUT'
};


//reducers.tsx
import Types from './types';
import State from './state';
import { Reducer, AnyAction } from 'redux';

const initialState: State = {
  user: null,
  isLoggedIn: false
};

export default class {
  reducer: Reducer<State> = (
    state: State = initialState,
    action: AnyAction
  ) => {
    // brahbrah
  };
}

//index.tsx
import reducer from './reducers';
import Types from './types';
import State from './state';

export default {
  reducer,
  Types,
  // How to export State in this default export?
};

但我不知道如何在index.tsx中导出状态接口的定义。

当我简单地将State放在导出中时，它告诉我'State' only refers to a type, but is being used as a value here.并且我理解这是错误的方式，但是导出这个定义需要什么？

Answer 1

问题是您正在尝试导出对象，但只有在编译之前存在Typescript类型和接口。对象的价值是什么？

// Typescript
interface Foo {};

export default {
  Foo,
};

// Compiled Javascript
export default {
  Foo: ???
};

我同意TS支持这种形式是合乎逻辑的，因为你可以单独导出接口，但据我所知，你现在不能这样做，你需要一个单独的导出。

export interface Foo {};

export default {
  // Rest of the things
};