鉴别器的OpenAPI 3.0.2多态性

Question

尝试使用的OpenAPI 3.0.2实现多态性。

Type1:
  type: object
  required:
  - dn
  - typeOfType
  properties:
    dn:
      description: Description
      type: string
    typeOfType:
      type: string
      enum:
        - Type2
        - Type3
  discriminator:
    propertyName: typeOfType
Type2:
  allOf:
  - $ref: '#/components/schemas/Type1'
  - type: object
    properties:
      name:
        $ref: '#/components/schemas/name' #abstract object
    required:
    - name
Type3:
  allOf:
  - $ref: '#/components/schemas/Type1'
  - type: object
    properties:
      surname:
        $ref: '#/components/schemas/surname' #abstract object
    required:
    - surname

我生成的代码是这样的：

@Validated
@JsonTypeInfo(use = JsonTypeInfo.Id.NAME, include = JsonTypeInfo.As.PROPERTY, property = "Discriminator{propertyName='typeOfType', mapping=null}", visible = true )
@JsonSubTypes({
@JsonSubTypes.Type(value = WniosekEkwU1.class, name = "Type1"),
@JsonSubTypes.Type(value = WniosekEkwU1A.class, name = "Type2"),
})
public class Type1  implements Serializable {
private static final long serialVersionUID = 1L;
...
}

综上，多态是行不通的。我不知道如果我的发电机工作正常时，它会创建property = "Discriminator{propertyName='typeOfType', mapping=null}"。我找不到在哪里产生类似代码的任何实例。当我将这段代码与property = "typeOfType"一切工作正常。

是我的代码错误或更多的配置是必需的？

我也端点测试这个类。我收到错误：

Resolved exception caused by handler execution:  org.springframework.http.converter.HttpMessageNotReadableException: 
JSON parse error: Missing type id when trying to resolve subtype of [simple type, class pl.asdf.asdf.asdf.gen.model.type1]: missing type id property 
'Discriminator{propertyName='typeOfType', mapping=null}' (for POJO property 'type1'); nested exception is com.fasterxml.jackson.databind.exc.InvalidTypeIdException: 
Missing type id when trying to resolve subtype of [simple type, class pl.asdf.asdf.asdf.gen.model.Type1]: 
missing type id property 'Discriminator{propertyName='typeOfType', mapping=null}' (for POJO property 'type1')

我不明白，当我修改上述属性此错误。我想它是连接。有没有什么解决办法吗？

Answer 1

此错误是固定在当前的3.0.5-快照：https://github.com/swagger-api/swagger-codegen-generators/issues/291

在你的代码的例子，我想提的唯一一件事就是删除枚举定义的属性typeOfType

这应该是足够了：

Type1:
  type: object
  discriminator:
    propertyName: typeOfType
  required:
  - dn
  - typeOfType
  properties:
    dn:
      description: Description
      type: string
    typeOfType:
      type: string