借用的数据逃逸到关联函数之外

Question

我是 Rust 新手，并尝试通过围绕它创建一些东西来学习该语言。

面对这个问题，

self

在此函数内有效，但闭包是

async

，因此它可能会在此函数的生命周期之后执行，并且闭包捕获

self

。我明白了问题所在。但我该怎么办呢？我明白这与寿命有关。但有人能告诉我解决方案是什么吗？

pub async fn run(&mut self) -> Result<i32, &str> {
    .
    .
    .

    match server.accept().await {
        Ok(p) => {
            tokio::spawn(async {
                self.handle_temp_connection(p)
            });
        },
        Err(err) => {
            println!("Some problem accepting a connection.")
        }
    }
}

fn handle_temp_connection(&self, p_socket_addr: (TcpStream, SocketAddr)) {
    ...
}

错误：

error[E0521]: borrowed data escapes outside of associated function
  --> src/app.rs:34:21
   |
20 |       pub async fn run(&mut self) -> Result<i32, &str> {
   |                        ---------
   |                        |
   |                        `self` is a reference that is only valid in the associated function body
   |                        let's call the lifetime of this reference `'1`
...
34 | /                     tokio::spawn(async {
35 | |                         self.handle_temp_connection(p)
36 | |                     });
   | |                      ^
   | |                      |
   | |______________________`self` escapes the associated function body here
   |                        argument requires that `'1` must outlive `'static`