我有2个约会。并且需要以这种格式${y}year ${w}weeks ${d}d
为此,我创建了函数。这是代码
setTotalDuration(): void {
const formattedFrom = moment(this.startDate).format('YYYY-MM-DD HH:mm:ss');
const formattedTo = moment(this.endDate).format('YYYY-MM-DD HH:mm:ss');
const duration = moment.duration(moment(formattedTo).diff(moment(formattedFrom)));
const y = Math.floor(duration.asYears());
const w = Math.floor(duration.asWeeks() - y * moment().weeksInYear());
const d = Math.floor(duration.asDays() - w * 7);
this.totalDuration = ` ${y}year ${w}weeks ${d}d`;
}
它无法正常工作,现在如果我通过例如startDate-19/02/2020和endDate-19/02/2021,我得到的持续时间-1年-1周373d。但我需要获得1年0周0d
我的问题在哪里?
我希望这就是你想要的。您可以得到以年为单位的差额,并将其添加到初始日期。然后获得以周为单位的差异,并将其再次添加到初始日期。
var moment = require("moment");
var a = moment(["2021", "02", "20"]);
var b = moment(["2020", "02", "19"]);
var years = a.diff(b, "year");
b.add(years, "years");
var weeks = a.diff(b, "week");
b.add(weeks, "weeks");
var days = a.diff(b, "days");
console.log(years + " years " + weeks + " weeks " + days + " days");
尝试此代码:
var now = moment(new Date()); //todays date
var end = moment("2020-02-16"); // another date
var duration = moment.duration(now.diff(end));
var days = duration.asDays();