具有随机数量条件的For循环

Question

我有这个用于在 Python 中过滤列表的代码：

# not working part
column_to_check_for_include = [1,2] # random result possible , could as well be [0] or [0,1,2]
column_to_check_for_exclude = [0,2,3] # random result possible , could as well be [0] or [0,1,2]

#Working part to update
content = [['John', 'is', 'cool','sometimes'],['Paul', 'is', 'bad','everytime'],['Ringo', 'may be', 'great', 'sometimes'],['Georges', 'must be', 'small', 'yesterday']]
include_criteria = ['is','must be']
exclude_criteria = ['bad','sometimes']

for row in content :
    if all(exclude not in row[0] and exclude not in row[2] and exclude not in row[3] for exclude in exclude_criteria):
        if any(include in row[1] or include in row[2] for include in include_criteria):
            print(row)
            # output ['Georges', 'must be', 'small', 'yesterday']

我想通过将所有

row[number]

替换为列表

column_to_check_for_include

和

column_to_check_for_exclude

的相应实例来执行相同的操作，因为知道这两个列表内容每次用户更新时都会更改。

类似的东西：

for row in content :
    if all(exclude not in row[column_to_check_for_exclude[0]] and exclude not in row[column_to_check_for_exclude[1]] and exclude not in row[column_to_check_for_exclude[2]] for exclude in exclude_criteria):
        if any(include in row[column_to_check_for_include[0]] or include in row[column_to_check_for_include[1]] for include in include_criteria):
            print(row)

也许我需要重新思考整个方法，但我不知道如何处理

if

语句中条件数量会发生变化的事实（取决于列表中的项目数量）。

谢谢

Answer 1

解决此问题的一种方法是：

for row in content :
    e=0
    i=0
    for exclude in exclude_criteria:
        if exclude in row:
            e=e+1
    for include in include_criteria:
        if include in row:
            i=i+1
    if i>0 and e==0:
        print(i,e,row)