这是打印结果的输出
(datetime.datetime(2018, 11, 30, 19, 52, 32, 927000),)
(None,)
(datetime.datetime(2018, 10, 17, 21, 39, 37, 163000),)
(datetime.datetime(2016, 12, 30, 20, 14, 23, 133000),)
(datetime.datetime(2018, 10, 17, 21, 31, 21, 853000),)
(datetime.datetime(2017, 2, 27, 21, 26, 51, 307000),)
(datetime.datetime(2018, 12, 20, 20, 35, 29, 997000),)
(datetime.datetime(2019, 9, 5, 15, 29, 22, 967000),)
(datetime.datetime(2018, 8, 13, 21, 57, 3, 307000),)
(datetime.datetime(2018, 10, 17, 21, 28, 23, 60000),)
这是我所拥有的
for result in cursor.fetchall(): print(result) result = datetime.strptime(str(result), '%Y-%m-%d') #client.edit_record(rid = result , fields = {'99' : '1' }, database=CONTACTS_TABLE) cursor.commit() cursor.close()
这是我的错误
ValueError: time data '(datetime.datetime(2018, 8, 21, 14, 14, 18, 233000),)' does not match format '%Y-%m-%d'
任何输入表示赞赏!
如果您要保存一个str,我建议做这样的事情:
for result in cursor.fetchall():
print(result)
result = '%d-%d-%d' % (result[0].year, result[0].month, result[0].day)
或者如果要保存日期对象,只需使用该值创建一个新的datetime.date