我需要重新排列层次结构。将出现在段落之后的列表(及其内容)移动到段落内部(如下同级),同时将其余数据保留在当前位置。
备注:
我对 XSL 比较陌生,不确定如何处理这个问题,因为它们目前是兄弟姐妹
我还没有尝试任何事情,因为我不知道如何解决这个问题。
谢谢
输入:
<section>
<para updated="20240206"><para.text>This is some para text.</para.text></para>
<para updated="20240206"><para.text>This is some para text with a list following:</para.text></para>
<list updated="20240206">
<heading>
<name>List 1</name>
</heading>
<list.item updated="20240206"><designator>1)</designator>
<para><para.text>content of the list item</para.text></para>
</list.item>
<list.item updated="20240206"><designator>2)</designator>
<para><para.text>content of the list item</para.text></para>
</list.item>
<list.item updated="20240206"><designator>3)</designator>
<para><para.text>content of the list item</para.text></para>
</list.item>
</list>
<para updated="20240206"><para.text>This is some para text with a feature following:</para.text></para>
<feature><name>Feature does not move</name>
<para><para.text>Text of the feature</para.text></para></feature>
<para><para.text>This is a para with a nested list following</para.text></para>
<list updated="20240206">
<heading>
<name>List 2</name>
</heading>
<list.item updated="20240206"><designator>1)</designator>
<para><para.text>content of the list item</para.text></para>
</list.item>
<list.item updated="20240206"><designator>2)</designator>
<para><para.text>content of the list item</para.text></para>
<list updated="20240206">
<heading>
<name>List 3</name>
</heading>
<list.item updated="20240206"><designator>a)</designator>
<para><para.text>content of the list item</para.text></para>
</list.item>
<list.item updated="20240206"><designator>b)</designator>
<para><para.text>content of the list item</para.text></para>
</list.item>
<list.item updated="20240206"><designator>c)</designator>
<para><para.text>content of the list item</para.text></para>
</list.item>
</list>
</list.item>
<list.item updated="20240206"><designator>3)</designator>
<para><para.text>content of the list item</para.text></para>
<table updated="20240206"><name>This table does not move</name></table>
</list.item>
</list>
</section>
输出:
<section>
<para updated="20240206"><para.text>This is some para text.</para.text></para>
<para updated="20240206"><para.text>This is some para text with a list following:</para.text>
<list updated="20240206">
<heading>
<name>List 1</name>
</heading>
<list.item updated="20240206"><designator>1)</designator>
<para><para.text>content of the list item</para.text></para>
</list.item>
<list.item updated="20240206"><designator>2)</designator>
<para><para.text>content of the list item</para.text></para>
</list.item>
<list.item updated="20240206"><designator>3)</designator>
<para><para.text>content of the list item</para.text></para>
</list.item>
</list>
</para>
<para updated="20240206"><para.text>This is some para text with a feature following:</para.text></para>
<feature><name>Feature does not move</name>
<para><para.text>Text of the feature</para.text></para></feature>
<para><para.text>This is a para with a nested list following</para.text>
<list updated="20240206">
<heading>
<name>List 2</name>
</heading>
<list.item updated="20240206"><designator>1)</designator>
<para><para.text>content of the list item</para.text></para>
</list.item>
<list.item updated="20240206"><designator>2)</designator>
<para><para.text>content of the list item</para.text>
<list updated="20240206">
<heading>
<name>List 3</name>
</heading>
<list.item updated="20240206"><designator>a)</designator>
<para><para.text>content of the list item</para.text></para>
</list.item>
<list.item updated="20240206"><designator>b)</designator>
<para><para.text>content of the list item</para.text></para>
</list.item>
<list.item updated="20240206"><designator>c)</designator>
<para><para.text>content of the list item</para.text></para>
</list.item>
</list></para>
</list.item>
<list.item updated="20240206"><designator>3)</designator>
<para><para.text>content of the list item</para.text></para>
<table updated="20240206"><name>This table does not move</name></table>
</list.item>
</list>
</para>
</section>
尝试了以下操作,但它正在移动该段落之后出现的任何内容。
<!DOCTYPE xsl:stylesheet [<!-- Needed to escape entities to use them in the body of the stylesheet -->
<!ENTITY sect "&sect;">
]>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" omit-xml-declaration="no"/>
<!--************************************************************************************-->
<!--******* Stylesheet to move end para tag after list sibling **********-->
<!--************************************************************************************-->
<xsl:variable name='newline'>
<xsl:text>
</xsl:text>
</xsl:variable>
<!--================================================================-->
<!--======= Process Root ===========================================-->
<!--================================================================-->
<xsl:template match="/">
<xsl:apply-templates/>
</xsl:template>
<!--================================================================-->
<!--======= Process All Content ====================================-->
<!--================================================================-->
<xsl:template match="@* | node()">
<xsl:apply-templates select="@* | node()"/>
</xsl:template>
<!--=================================================================-->
<!--======== Get para and process =============-->
<!--=================================================================-->
<xsl:template match="*[para]">
<xsl:copy>
<xsl:apply-templates select="@*"/>
<xsl:for-each-group select="*" group-starting-with="para">
<xsl:choose>
<xsl:when test="self::para">
<xsl:copy>
<xsl:apply-templates select="@*, node(), subsequence(current-group(), 2)"/>
</xsl:copy>
</xsl:when>
<xsl:otherwise>
<xsl:apply-templates select="current-group()"/>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each-group>
</xsl:copy>
</xsl:template>
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
我认为这可能最好使用兄弟递归来处理。
处理一个节时,对其进行浅复制并处理其第一个子节:
<xsl:template match="section">
<xsl:copy>
<xsl:apply-templates select="*[1]" mode="sib"/>
</xsl:copy>
</xsl:template>
默认情况下,在处理某个部分的子级(包括列表元素)时,处理它并处理其下一个子级:
<xsl:template match="section/*" mode="sib">
<xsl:apply-templates select="."/>
<xsl:apply-templates select="following-sibling::*[1]" mode="sib"/>
</xsl:template>
处理para时,在结果元素内部处理以下列表元素,然后在外部处理以下非列表元素:
<xsl:template match="section/para" mode="sib">
<xsl:copy>
<xsl:apply-templates/>
<xsl:apply-templates select="following-sibling::*[1][self::list]"/> mode="sib"/>
</xsl:copy>
<xsl:apply-templates select="following-sibling::*[not(self::list)][1]" mode="sib"/>
</xsl:template>
XSLT 3.0 的完整代码:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="3.0"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
exclude-result-prefixes="#all"
expand-text="yes">
<xsl:output method="html" indent="no" html-version="5"/>
<xsl:mode on-no-match="shallow-copy"/>
<xsl:template match="section">
<xsl:copy>
<xsl:apply-templates select="*[1]" mode="sib"/>
</xsl:copy>
</xsl:template>
<xsl:template match="section/*" mode="sib">
<xsl:apply-templates select="."/>
<xsl:apply-templates select="following-sibling::*[1]" mode="sib"/>
</xsl:template>
<xsl:template match="section/para" mode="sib">
<xsl:copy>
<xsl:apply-templates/>
<xsl:apply-templates select="following-sibling::*[1][self::list]" mode="sib"/>
</xsl:copy>
<xsl:apply-templates select="following-sibling::*[not(self::list)][1]" mode="sib"/>
</xsl:template>
</xsl:stylesheet>
对于 2.0(或者实际上 1.0),您必须将 xsl:mode 声明替换为标准身份模板规则。
抱歉,这对于初学者来说是一个相当高级的主题,但仅仅因为您是初学者并不总是意味着您可以从简单的问题开始!