按升序和降序对多个数组键进行排序，使用数字对字符串进行排序

Question

我有一个JavaScript对象数组：

这不是一个重复的问题。因为，我有一个有2个键的对象数组（key，count）。我想排序，key升序（字符串）和value降序（数字）顺序。

 var array = [
  {"count":7,"key":"a"},
  {"count":10,"key":"b"},
  {"count":5,"key":"c"},
  {"count":10,"key":"a"},
  {"count":3,"key":"d"}
];

期望的输出：

     var array = [
      {"count":10,"key":"a"},
      {"count":10,"key":"b"},
      {"count":7,"key":"a"},
      {"count":5,"key":"c"},
      {"count":3,"key":"d"}
    ];

var array = [{"count":7,"key":"a"},{"count":10,"key":"b"},{"count":5,"key":"c"},{"count":10,"key":"a"},{"count":3,"key":"d"}];

console.log(array.sort((a, b) => (b.count - a.count)));

key排序为升序

count排序下降

我用array.sort((a, b) => (b.count - a.count))方法进行排序计数。但是，无法弄清楚如何对对象的两个键进行排序。

Answer 1

试试以下

var array = [{"count":7,"key":"a"},{"count":10,"key":"b"},{"count":5,"key":"c"},{"count":10,"key":"a"},{"count":3,"key":"d"}];

console.log(array.sort((a, b) => {
  if(a.count === b.count) return a.key.localeCompare(b.key);
  return b.count - a.count;
}));

Answer 2

您必须将逻辑||运算符与localeCompare函数结合使用。

如果||结果为零，则b.count - a.count运算符将仅考虑第二个分量。

var array = [{"count":7,"key":"a"},{"count":10,"key":"b"},{"count":5,"key":"c"},{"count":10,"key":"a"},{"count":3,"key":"d"}];

console.log(array.sort((a, b) => b.count - a.count || a.key.localeCompare(b.key)));