我的样本数据:
id role_id permission_id access_granted user_id
------------------------------------------------------------------
1 1 10 1 115
------------------------------------------------------------------
2 1 5 1 115
------------------------------------------------------------------
3 2 10 0 115
------------------------------------------------------------------
4 2 8 0 115
------------------------------------------------------------------
使用permission_id进行分组,对于重复的permission_id,结果应该具有值为true的行。正如我们所看到的,查询是按permission_id分组的,并且为permission_id 10选择了值为true的行,而对于其他行,权限id不会重复,因此值false被按原样选择。
预期结果:
id role_id permission_id access_granted user_id
------------------------------------------------------------------
1 1 10 1 115
------------------------------------------------------------------
2 1 5 1 115
------------------------------------------------------------------
4 2 8 0 115
------------------------------------------------------------------
下面是我尝试获取上述结果的查询。
select id, role_id, permission_id,
case when max(access_granted) = true then true else false end as access_granted,
user_id as user_id
from temp_permission group by permission_id;
需要优化且真实的查询,在任何情况下都不会失败。
创建表查询
CREATE TABLE temp_permission (
id int auto_increment primary key,
role_id int,
permission_id int,
access_granted tinyInt(1),
user_id int
);
根据屏幕截图对表进行虚拟数据查询
INSERT INTO `temp_permission` (`id`, `role_id`, `permission_id`, `access_granted`, `user_id`) VALUES ('1', '1', '10', '1', '115');
INSERT INTO `temp_permission` (`id`, `role_id`, `permission_id`, `access_granted`, `user_id`) VALUES ('2', '1', '5', '1', '115');
INSERT INTO `temp_permission` (`id`, `role_id`, `permission_id`, `access_granted`, `user_id`) VALUES ('3', '2', '10', '0', '115');
INSERT INTO `temp_permission` (`id`, `role_id`, `permission_id`, `access_granted`, `user_id`) VALUES ('4', '2', '8', '0', '115');
如果您无法将数据插入 access_granted 列,请替换
1 = b'1' & 0 = b'0'
您可以简单地根据
permission_id
和 access_granted
按降序排列行,然后根据 permission_id
选择不同的行。比如:
WITH ordered_rows AS (
SELECT id, role_id, permission_id, access_granted, user_id,
ROW_NUMBER() OVER (PARTITION BY permission_id ORDER BY access_granted DESC) as row_num
FROM temp_permission
)
SELECT id, role_id, permission_id, access_granted, user_id
FROM ordered_rows
WHERE row_num = 1;